添加到不同表时删除一行答案

【问题标题】：Remove one row when it is added to different table添加到不同表时删除一行
【发布时间】：2015-05-19 19:08:40
【问题描述】：

我有两张桌子

已注册的事件和事件，但我想显示按下按钮时它会将事件从事件中删除为已注册的事件。但我无法删除事件本身我可以隐藏它，使它不会出现在网页的表格中吗？？

我正在使用 CodeIgniter

![Cassey 的 Graded Scratch Races 活动在两个表格中] [1]

我没有 10 声望，所以这里有一个图片链接 https://www.dropbox.com/s/uzyvblmim0e1s5v/2015-05-19%2013_13_00-Eastern%20Veterans%20Cycling.png?dl=0

型号

function getAll()
{
// get all the records from the schools table

$this->db->select('*');
$this->db->from('tblMeetRace as met');
$this->db->join('tblLocation as loc', 'loc.intLocationID = met.intLocationID');
$this->db->join('tblEvent as eve', 'eve.intEventID = met.intEventID');
//$this->db->Where('intMemberID = 1' );
$query = $this->db->get();


// if the number of rows returned is more than 0
if( $query->num_rows() > 0) {
    // loop through each record (row) and place that
    // record into an array called $data
    foreach ($query->result() as $row) {
        $data[] = $row;
    }
}
$query->free_result();
// return the array to the controller
return $data;



function getAll1()
{
    // get all the records from the schools table

    $this->db->select('*');
    $this->db->from('tblMeetRace as met');
    $this->db->join('tblLocation as loc', 'loc.intLocationID = met.intLocationID');
    $this->db->join('tblRegistration as reg', 'reg.intMeetRaceID = met.intMeetRaceID');
    $this->db->join('tblEvent as eve', 'eve.intEventID = met.intEventID');
    $this->db->Where('intMemberID = 1' );
    $query = $this->db->get();

    // if the number of rows returned is more than 0
    if( $query->num_rows() > 0) {
        // loop through each record (row) and place that
        // record into an array called $data
        foreach ($query->result() as $row1) {
            $data1[] = $row1;
        }
    }
    $query->free_result();
    // return the array to the controller
    return $data1;
}

控制器

public function getallevents() {
    $this->load->model('events_model');
    $data['records'] = $this->events_model->getAll();
    $data1['records1'] = $this->events_model->getAll1();
    $data3 = $data + $data1;
    $this->load->view('view-events', $data3);
}

查看

        <!-- code for table of schools -->
    <div class="container proper-content">
        <div class="bs-example table-responsive">
            <h3>Unregistered Events</h3>
            <table class="table table-striped table-bordered table-hover">
                <thead class="tablebackground">
                <tr>
                    <th>&nbsp;&nbsp;Meet race ID</th>
                    <th>&nbsp;&nbsp;Event Name</th>
                    <th>&nbsp;&nbsp;Location</th>
                    <th>&nbsp;&nbsp;Date</th>
                    <th>&nbsp;&nbsp;Time</th>
                    <th>&nbsp;&nbsp;Register</th>
                </tr>
                </thead>
                <tbody>

                <?php

                foreach ($records as $row):
                    echo "<tr>";
                    echo "<td> $row->intMeetRaceID</td>";
                    //echo "<td> $row->intEventID</td>";
                    echo "<td> $row->strEventDescription</td>";
                    echo "<td> $row->strLocationName</td>";
                    echo "<td> $row->datDate</td>";
                    echo "<td> $row->timTime</td>";
                    echo "<td><a class='btn btn-success btn-sm'>Register</a></td>";
                    echo "</tr>";
                endforeach;


                ?>
                </tbody>
            </table>
            <h3>Registered Events</h3>

            <table class="table table-striped table-bordered table-hover">
                <thead class="tablebackground">
                <tr>
                 <!--   <th>&nbsp;&nbsp;User-ID #</th> -->
                    <th>&nbsp;&nbsp;Event Name</th>
                    <th>&nbsp;&nbsp;Location</th>
                    <th>&nbsp;&nbsp;Date</th>
                    <th>&nbsp;&nbsp;Time</th>
                    <th>&nbsp;&nbsp;UnRegister</th>
                </tr>
                </thead>
                <tbody>
                <?php
                    foreach ($records1 as $row1):
                        echo "<tr>";
                        //echo "<td> $row->intMemberID</td>";
                        //echo "<td> $row1->intEventID</td>";
                        echo "<td> $row1->strEventDescription</td>";
                        echo "<td> $row1->strLocationName</td>";
                        echo "<td> $row1->datDate</td>";
                        echo "<td> $row1->timTime</td>";
                        echo "<td><a class='btn btn-danger btn-sm'>Delete</a></td>";
                        echo "</tr>";
                    endforeach;

【问题讨论】：

为什么有两张桌子？保存所有数据的单个表将绰绰有余。只需添加一个注册字段，其值为 0/1 或 Y/N。那么切换这个标志就很简单了。
这只是我的例子，我还有其他表格和其他信息
在程序中思考。您需要读取一个，删除它，然后将其写入另一个，但是如果您想确保它在那里，您可以做一个 where 以确保每个字段都匹配。
触发器怎么样？

标签： php html mysql sql codeigniter

【解决方案1】：

尽管您可以更轻松地完成这些事情，但您可以尝试像这样扩展您的第一个查询 - 如果我理解正确的话：

$this->db->select('*');
$this->db->from('tblMeetRace as met');
$this->db->join('tblLocation as loc', 'loc.intLocationID = met.intLocationID');
$this->db->join('tblEvent as eve', 'eve.intEventID = met.intEventID');
$this->db->join('tblRegistration as reg', 'reg.intMeetRaceID = met.intMeetRaceID', 'left');
$this->db->where(array("met.intMeetRaceID" => NULL));

【讨论】：