【发布时间】：2012-03-06 20:16:17
【问题描述】：
我正在创建一个用户面板，用户可以在其中注册和上传图像。一旦他们登录，他们可能会决定编辑该图像，因此我想执行更新查询以将新图像添加到该位置并将新图像附加到他们的 mysql 数据中。
所以当我提交代码时发生了什么：我收到一条错误消息：：抱歉，上传您的文件时出现问题。
希望有人可以告诉我为什么这会给我一个错误。 PS 当他们第一次注册上传文件时，我已经在使用这个位置。但这当然不应该有任何问题。我发现的另一个问题是照片的 MYSQL 表中没有成功插入任何内容。
代码如下：
表：管理员
CREATE TABLE IF NOT EXISTS `admin` (
`id` int(3) NOT NULL auto_increment,
`UserName` varchar(30) default NULL,
`PassWord` varchar(30) default NULL,
`name` varchar(30) default NULL,
`mainContent` varchar(2000) default NULL COMMENT 'maincontent test',
`photo` varchar(400) NOT NULL COMMENT 'Picture1',
PRIMARY KEY (`id`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=64 ;
假设用户已经登录到他们的用户面板：他们点击链接到他们的 ID 的编辑按钮。
所以它们出现在编辑页面：
EDIT.PHP
<?php
session_start();
$UserName = $_SESSION['UserName'];
require("checkLoginSession.php");
$adminid = $_GET['id'];
// Connect to server and select database.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");
echo("Logged In As: $UserName");
echo "<br />";
echo("We are editing Data for ID: $adminid");
echo "<br />";
echo "<a href=test.php>Go back to panel</a>";
$id=$_GET['id'];
// Retrieve data from database
$sql="SELECT * FROM admin WHERE id='$id'";
$result=mysql_query($sql) or die(mysql_error());
$rows=mysql_fetch_array($result);
?>
<table width="400" border="0" cellspacing="1" cellpadding="0">
<tr>
<form name="form1" method="post" action="update_ac.php">
<td>
<table width="100%" border="0" cellspacing="1" cellpadding="0">
<tr>
<td> </td>
<td colspan="3"><strong>Update data in mysql</strong> </td>
</tr>
<tr>
<td align="center"> </td>
<td align="center"> </td>
<td align="center"> </td>
<td align="center"> </td>
</tr>
<tr>
<td align="center"> </td>
<td align="center"><strong>Name</strong></td>
<td align="center"><strong>Main Content</strong></td>
<td align="center"><strong>Image Locatoin</strong></td>
</tr>
<tr>
<td> </td>
<td align="center"><input name="name" type="text" id="name" value="<? echo $rows['name']; ?>"></td>
<td align="center"><input name="mainContent" type="text" id="mainContent" value="<? echo $rows['mainContent']; ?>" size="15"></td>
<td align="center"><input name="photo" type="file" id="photo">
</tr>
<tr>
<td> </td>
<td><input name="id" type="hidden" id="id" value="<? echo $rows['id']; ?>"></td>
<td align="center"><input type="submit" name="Submit" value="Submit"></td>
<td> </td>
</tr>
</table>
</td>
</form>
</tr>
</table>
<?
mysql_close();
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Edit Page</title>
</head>
<body>
<h2>Edit Page (<?php echo ("$adminid"); ?>)</h2>
<a href="test.php"><img src="backtopanel.jpg" alt="back to panel" width="454" height="85" border="0" longdesc="back to panel" /></a>
</body>
</html>
update_ac.php
<?php
session_start();
$UserName = $_SESSION['UserName'];
require("checkLoginSession.php");
include "common.php";
DBConnect();
$Link = mysql_connect($Host, $User, $Password);
$id = $_POST['id'];
$target = "images/";
$target = $target . basename( $_FILES['photo']['name']);
// Connect to server and select database.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");
// update data in mysql database
$_POST = array_map("mysql_real_escape_string", $_POST);
$firstName = $_POST["name"];
$mainText = $_POST["mainContent"];
$pic=($_FILES['photo']['name']);
//
$sql="UPDATE admin SET name='$firstName', mainContent='$mainText', photo='$pic' WHERE id='$id'";
echo $sql;
//
if (mysql_db_query ($DBName, $sql, $Link)){
print ("A record was created <br><a href=index.php> return to index </a>\n");
//Writes the photo to the server
if(move_uploaded_file($_FILES['photo']['tmp_name'], $target))
{
//Tells you if its all ok
echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded, and your information has been added to the directory";
}
else {
//Gives and error if its not
echo "Sorry, there was a problem uploading your file.";
}
} else {
print ("Record not created");
}
mysql_close($Link);
?>
【问题讨论】：
-
听起来像是权限问题。
标签： php mysql html css database