BeautifulSoup 获取一行标签之间的文本答案

【问题标题】：BeautifulSoup get text between tags for one lineBeautifulSoup 获取一行标签之间的文本
【发布时间】：2021-12-02 21:49:42
【问题描述】：

我有一堆 GCOV 分支和行覆盖工具的 HTML 文档，文件如下所示：

<tr>
<td align="right" class="lineno"><pre>224</pre></td>
<td align="right" class="linebranch"><span class="takenBranch" title="Branch 1 taken 329 times">&check;</span><span class="notTakenBranch" title="Branch 2 not taken">&cross;</span><span class="notTakenBranch" title="Branch 4 not taken">&cross;</span><span class="takenBranch" title="Branch 5 taken 329 times">&check;</span><br/><span class="notTakenBranch" title="Branch 6 not taken">&cross;</span><span class="takenBranch" title="Branch 7 taken 329 times">&check;</span></td>
<td align="right" class="linecount coveredLine"><pre>329</pre></td>
<td align="left" class="src coveredLine"><pre>        line of C++ code</pre></td>
</tr>

<tr>
<td align="right" class="lineno"><pre>225</pre></td>
<td align="right" class="linebranch"></td>
<td align="right" class="linecount uncoveredLine"><pre></pre></td>
<td align="left" class="src uncoveredLine"><pre>   another line of  C++ code;</pre></td>
</tr>

我想提取文本“(another) line of C++”代码，理想情况下还有行号，所以输出如下所示：

224 line of C++ code
225 another line of C++ code

我尝试使用 BeautifulSoup，但它没有提供请求的输出，我的代码如下所示：

from itertools import islice
import codecs
import glob
from ntpath import join
import os
from bs4 import BeautifulSoup

lineNo = "<td align=\"right\" class=\"lineNo\"><pre>"
linetextCovered = "<td align=\"left\" class=\"src coveredLine\"><pre>"
linetextNotCovered = "<td align=\"left\" class=\"src uncoveredLine\"><pre>"
open('Output.txt', 'w').close() #Erase any content of Output.txt file

for filepath in glob.iglob('path/To/Reports/*.html'):
    with codecs.open(os.path.join(filepath), "r") as inputFile, open('Output.txt',"a") as outputFile:
        for num, line in enumerate(inputFile, 1):
            if lineNo in line:
                inputSoup = BeautifulSoup(line)
                text = inputSoup.getText()
                outputFile.write("".join(islice(text, 1) + "\t"))
            if linetextCovered or linetextNotCovered in line:
                inputSoup = BeautifulSoup(line)
                text = inputSoup.getText()
                outputFile.write("".join(islice(text, 4)))
            outputFile.write("\n")
print("Done")

但输出看起来像这样

/* L
a:li
{

colo
text
}

我做错了什么？非常感谢您的帮助。

【问题讨论】：

标签： python html parsing beautifulsoup

【解决方案1】：

你可以这样做：

from bs4 import BeautifulSoup

html = '''
<tr>
<td align="right" class="lineno"><pre>224</pre></td>
<td align="right" class="linebranch"><span class="takenBranch" title="Branch 1 taken 329 times">&check;</span><span class="notTakenBranch" title="Branch 2 not taken">&cross;</span><span class="notTakenBranch" title="Branch 4 not taken">&cross;</span><span class="takenBranch" title="Branch 5 taken 329 times">&check;</span><br/><span class="notTakenBranch" title="Branch 6 not taken">&cross;</span><span class="takenBranch" title="Branch 7 taken 329 times">&check;</span></td>
<td align="right" class="linecount coveredLine"><pre>329</pre></td>
<td align="left" class="src coveredLine"><pre>        line of C++ code</pre></td>
</tr>

<tr>
<td align="right" class="lineno"><pre>225</pre></td>
<td align="right" class="linebranch"></td>
<td align="right" class="linecount uncoveredLine"><pre></pre></td>
<td align="left" class="src uncoveredLine"><pre>   another line of  C++ code;</pre></td>
</tr>
'''


for tr in BeautifulSoup(html.encode(), 'html.parser').find_all('tr'):
    lineno  = tr.find('td',{'class':'src'}).text.strip()
    src     = tr.find('td', {'class':'lineno'}).text.strip()
    print(lineno, src)

【讨论】：