使用 c++11 而不是 c++14 时的未知运行时

Question

我在编译代码时遇到了以下错误。我试图通过我的代码查找转换错误，但我没有看到它。

编译在编译和运行时发生错误 g++ (GCC) 8.3.1 20191121（红帽 8.3.1-5）

当我在 Ubuntu 上编译时，我没有收到任何错误并且它运行。 (Ubuntu 7.4.0-1ubuntu1~18.04.1) 7.4.0

这是错误。

/builddir/build/BUILD/gcc-8.3.1-20191121/obj-x86_64-redhat-linux/x86_64-redhat-linux/libstdc++-v3/include/bits/basic_string.h:1067: std::__cxx11::basic_string<_CharT, _Traits, _Alloc>::reference std::__cxx11::basic_string<_CharT, _Traits, _Alloc>::operator[](std::__cxx11::basic_string<_CharT, _Traits, _Alloc>::size_type) [with _CharT = char; _Traits = std::char_traits<char>; _Alloc = std::allocator<char>; std::__cxx11::basic_string<_CharT, _Traits, _Alloc>::reference = char&; std::__cxx11::basic_string<_CharT, _Traits, _Alloc>::size_type = long unsigned int]: Assertion '__pos <= size()' failed.
Aborted (core dumped)

main.cpp

//Here is where I can take a string and generate a pseudo-random password from it 
std::string passGen(std::string user)
{
    char passwordArray[9];
    int achar;
    srand (time(0));    
    for (int x=0; x <= 8; x++)
    {
        achar = (user[x] * (rand()%100))%26 + 97;
        passwordArray[x] = (char)achar;
    }   
    return passwordArray;
}
        
//This reads the filename that is passed in and builds the linked list of names and uses the password generator and generates passwords for each username. 
void readFile(std::string newFile){
    ifstream inFile(newFile);
    std::string firstWord;
    
    while(inFile >> firstWord)
    {
        listOfNames->InsertAtHead(firstWord, passGen(firstWord));
        inFile.ignore(numeric_limits<streamsize>::max(), '\n');
    }
    inFile.close();
}

Answer 1

我发现问题出在哪里。在这里：

{
    char passwordArray[9];
    int achar;
    srand (time(0));    
    for (int x=0; x <= 8; x++)
    {
        achar = (user[x] * (rand()%100))%26 + 97;
        passwordArray[x] = (char)achar;
    }   
    return passwordArray;
}

当我将短于 9 个字符的名称传递给此方法时发生错误。如果名称太短，则 user[x] 将无权访问。我不得不将其更改为

user[x % user.size()]

我没有意识到编译器之间存在如此大的差异。看到我的错误后，我很惊讶它在 Ubuntu 中成功运行。