如何从每个段落中仅选择 1 个复选框？

Question

我正在处理 html 调查页面，要求从调查的每一行中仅选择 1 个复选框，调查选项可能不同，请参见下面的屏幕和 html：

使用的 HTML

 <div class="firstrow"><div class="srno"><p>1.</p></div><div class="survey"><span>I am satisfied with the quality, reliability and speed of the computer I use.</span></div></div>
    <div class="options">
        <span class="optpadding"><input type="checkbox" name="Strongly agree" value="Strongly agree"><span>Strongly agree</span></span>
        <span class="optpadding"><input type="checkbox" name="Agree" value="Agree"><span>Agree</span></span>
        <span class="optpadding"><input type="checkbox" name="Disagree" value="Disagree"><span>Disagree</span></span>
        <span class="optpadding"><input type="checkbox" name="Strongly disagree" value="Strongly disagree"><span>Strongly disagree</span></span>
    </div>
<div class="firstrow"><div class="srno"><p>2.</p></div><div class="survey"><span>The Software currently installed on my computer is adequate for my job function.</span></div></div>
   <div class="options">
        <span class="optpadding"><input type="checkbox" name="Strongly agree" value="Strongly agree"><span>Strongly agree</span></span>
        <span class="optpadding"><input type="checkbox" name="Agree" value="Agree"><span>Agree</span></span>
        <span class="optpadding"><input type="checkbox" name="Disagree" value="Disagree"><span>Disagree</span></span>
        <span class="optpadding"><input type="checkbox" name="Strongly disagree" value="Strongly disagree"><span>Strongly disagree</span></span>
    </div>

如何使用 jquery 实现这一点，我已经尝试了很多，但当只有 1 个调查问题时取得了成功。当我选择另一个问题复选框时，这将删除以前选择的问题复选框。

Jquery 使用

$(function () {
   $('input:checkbox').click(function () {
      if ($(this).is(':checked')) {
          $('input:checkbox').not(this).prop('checked', false);
       }
   });
})

如何解决这个问题？

Answer 1

注意：-其实最好使用单选按钮，这样就不需要jQuery了。

但是，如果您想使用复选框和 jQuery，请执行以下操作：-

$(function () {
   $('input:checkbox').click(function () {
      if ($(this).is(':checked')) {
          $(this).parent().siblings().children("input:checkbox").prop('checked', false);
       }
   });
})

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="firstrow"><div class="srno"><p>1.</p></div><div class="survey"><span>I am satisfied with the quality, reliability and speed of the computer I use.</span></div></div>
    <div class="options">
        <span class="optpadding"><input type="checkbox" name="Strongly agree" value="Strongly agree"><span>Strongly agree</span></span>
        <span class="optpadding"><input type="checkbox" name="Agree" value="Agree"><span>Agree</span></span>
        <span class="optpadding"><input type="checkbox" name="Disagree" value="Disagree"><span>Disagree</span></span>
        <span class="optpadding"><input type="checkbox" name="Strongly disagree" value="Strongly disagree"><span>Strongly disagree</span></span>
    </div>
<div class="firstrow"><div class="srno"><p>2.</p></div><div class="survey"><span>The Software currently installed on my computer is adequate for my job function.</span></div></div>
   <div class="options">
        <span class="optpadding"><input type="checkbox" name="Strongly agree" value="Strongly agree"><span>Strongly agree</span></span>
        <span class="optpadding"><input type="checkbox" name="Agree" value="Agree"><span>Agree</span></span>
        <span class="optpadding"><input type="checkbox" name="Disagree" value="Disagree"><span>Disagree</span></span>
        <span class="optpadding"><input type="checkbox" name="Strongly disagree" value="Strongly disagree"><span>Strongly disagree</span></span>
    </div>

Answer 2

要在多个选项中只选择一个选项，而不是使用checkbox，而是使用radio 并为属于一个类别的所有收音机赋予相同的名称，以便一次只能检查一个收音机。

例如：

<p>Topic 1
  <input type="radio" name="topic1">One
  <input type="radio" name="topic1">Two
</p>

<p>Topic 2
  <input type="radio" name="topic2">One
  <input type="radio" name="topic2">Two
</p>

Answer 3

使用<input type="radio" /> 而不是<input type="checkbox" />

但要修复您的 jQuery，请使用 .siblings() 而不是 .not(this)

Answer 4

试试这个代码100%工作：

演示： https://output.jsbin.com/ketunanizo

https://jsbin.com/ketunanizo/edit?html,js,output

HTML：

<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <meta name="viewport" content="width=device-width">
  <title>JS Bin</title>
  <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
</head>
<body>
<div class="firstrow"><div class="srno"><p>1.</p></div><div class="survey"><span>I am satisfied with the quality, reliability and speed of the computer I use.</span></div></div>
    <div class="options">
        <span class="optpadding"><input type="checkbox" name="Strongly agree" value="Strongly agree"><span>Strongly agree</span></span>
        <span class="optpadding"><input type="checkbox" name="Agree" value="Agree"><span>Agree</span></span>
        <span class="optpadding"><input type="checkbox" name="Disagree" value="Disagree"><span>Disagree</span></span>
        <span class="optpadding"><input type="checkbox" name="Strongly disagree" value="Strongly disagree"><span>Strongly disagree</span></span>
    </div>
<div class="firstrow"><div class="srno"><p>2.</p></div><div class="survey"><span>The Software currently installed on my computer is adequate for my job function.</span></div></div>
   <div class="options">
        <span class="optpadding"><input type="checkbox" name="Strongly agree" value="Strongly agree"><span>Strongly agree</span></span>
        <span class="optpadding"><input type="checkbox" name="Agree" value="Agree"><span>Agree</span></span>
        <span class="optpadding"><input type="checkbox" name="Disagree" value="Disagree"><span>Disagree</span></span>
        <span class="optpadding"><input type="checkbox" name="Strongly disagree" value="Strongly disagree"><span>Strongly disagree</span></span>
    </div>
</body>
</html>

JavaScript：

<script>
$(function () {
   $('input:checkbox').click(function () {
      if ($(this).is(':checked')) {
          $(this).closest('.options').find('input:checkbox').not(this).prop('checked', false);
       }
   });
})
</script>

Answer 5

试试这个，它肯定会奏效....

$('input:checkbox').click(function () {
  if ($(this).is(':checked')) {
      $(this).parent().siblings().children().prop('checked', false);
   }
});