【发布时间】:2022-01-30 03:08:16
【问题描述】:
我的主要目标是获取特定对象的信息。
$client = $adapter->getClient();
$objectInfo = $client->getObject(
[
'Bucket' => 'bucket-name',
'Key' => "key-name",
]
);
dd($objectInfo->toArray()["Body"]);
运行时,我得到了结果:
GuzzleHttp\Psr7\Stream {
-stream: stream resource {
wrapper_type: "PHP"
stream_type: "TEMP"
mode: "w+b"
unread_bytes: 0
seekable: true
uri: "php://temp"
options: []
}
-size: null
-seekable: true
-readable: true
-writable: true
-uri: "php://temp"
-customMetadata: []
}
任何解决它的想法将不胜感激。
【问题讨论】:
标签: laravel amazon-web-services amazon-s3 aws-sdk aws-php-sdk