如何在不刷新页面的情况下刷新 MySQL 查询的结果？

Question

我想定期刷新一次查询的结果，比如每 10-30 秒一次。我不确定如何将我在网上阅读的代码实现到我自己的代码中，因为很多时候场景不同。

MySQL 查询与我的 jQuery 和其他所有内容在同一页面上。

目前，我使用以下 PHP 代码检索 MySQL 表的值：

$result = mysqli_query($con,"SELECT * From auction WHERE category = 'Bathroom' ORDER BY ID DESC");


while($row = mysqli_fetch_array($result))
  {
    echo "<form name='auction' id='auction" . $row['ID'] . "'>
            <input type='hidden' name='id' value='" . $row['ID'] . "' />
            <div class='auction-thumb'>
                <div class='auction-name'>" . $row['Item'] . "</div>";
            echo "<img class='auction' src='" . $row['ImagePath'] . "' />";
            echo "<div class='auction-bid'>Current Bid: £<div class='nospace' id='" . $row['ID'] . "'>" . $row['CurrentBid'] . "</div></div>";
            echo "<div class='auction-bid'>Your Name: <input type='text' class='bidder' name='bidname' autocomplete='off'/></div>";
            echo "<div class='auction-bid'>Your Bid: <input type='text' class='auction-text' name='bid' autocomplete='off'/></div>";
            echo "<div class='auction-bid'><input type='submit' name='submit' value='Place Bid!' /></div>";
    echo "</div></form>";
  }
echo "</table>";

mysqli_close($con);

?>

这会检索多行并填充页面。

我想经常刷新或“重新运行”此查询，以便更新当前出价。

我已经有这个 jQuery 代码，它可以将新的出价发布到 PHP 页面，目前，查看此页面的任何其他人在手动刷新页面之前都不会看到新的出价，这不是很好。

    <script>
    $(document).ready(function(){
        $('form[name="auction"]').submit(function(){
            var id = $(this).find('input[name="id"]').val();
            var bidname = $(this).find('input[name="bidname"]').val();
            var bid = $(this).find('input[name="bid"]').val();
            var currentbid = $('#'+id).text();
            var itemdesc = $(this).find('.auction-name').text();

            if (bidname == '')
            {
                alert("No name!")
                return false;   
            }

            if (bid > currentbid)
            {
                alert("Bid is greater than current bid");   
            }
            else
            {
                alert("Bid is too low!");
                return false;   
            }

            $.ajax({
            type: "POST",
            url: "auction-handler.php",
            data: {bidname: bidname, bid: bid, id: id, itemdesc: itemdesc},
            success: function(data){
                window.location.reload();
            }
        });
        return false;

        }); 
    });
</script>

我的拍卖处理程序.php 代码：

<?php
ini_set('display_errors', 'On');
error_reporting(E_ALL | E_STRICT);

$con=mysqli_connect("xxxx","xxxx","xxxx","xxxx");

if (mysqli_connect_errno())
    {
            echo "Failed to connect to MySQL: " . mysqli_connect_error();
    }

$bidname = $_POST['bidname'];
$bid = $_POST['bid'];
$id = $_POST['id'];
$itemdesc = $_POST['itemdesc'];

$query = "UPDATE auction SET CurrentBid = '$bid', Bidder = '$bidname' WHERE ID = '$id'";

$query2 = "INSERT INTO auction_log (Item, Bid, Bidder) VALUES ('$itemdesc','$bid','$bidname')";



mysqli_query($con, $query) or die(mysqli_error());

mysqli_query($con, $query2) or die(mysqli_error());

mysqli_close($con);
?>

我在网上阅读的很多东西并没有真正帮助我，而且我太初学者了，无法自己正确编写。我真的很难理解如何去做，以及如何在我的场景中实现它。

非常感谢任何建议。

Answer 1

离你不远了。

你需要做的是将相关表的html替换为ajax请求的响应而不是重新加载整个页面。

所以而不是：

success: function(data){
            window.location.reload();
        }

你可以这样做：

success: function(data){
            $('#auction'+id).before(data).remove();
        }

编辑

周期性的ajax请求：

php:

//update-handler.php
$response = array();

$result = mysqli_query($con,"SELECT * From auction WHERE category = 'Bathroom' ORDER BY ID DESC");


 while($row = mysqli_fetch_array($result)){
  $response[] = (object)array('id'=>$row['ID'],'val'=>$row['CurrentBid']);
 // get all the updated rows and put them into response array;
 }

header('content-type=application/json');
exit(json_encode($response)); // send the json serialized response to jquery ajax

javascript：

var timeout = 30000 //30 seconds
setInterval(function () {

    $.ajax({
    type: "POST",
    url: "update-handler.php",
    success: function (data) {
        $(data).each(function (i, d) {  //loop though each bid amount from ajax response
            $('#auction' + d.id).find('.nospace').html(d.val); //nospace is not a good target name, but its the only unique selector for that div

        });
    }
    });
}, timeout);

Answer 2

<div id="results">
	...
</div>

<script>
var time = 30000;
function autoRefresh()
{
	$.ajax({
		type: "POST",
		dataType: "HMTL",
		url: "auction-handler.php",
		data: {bidname: bidname, bid: bid, id: id, itemdesc: itemdesc},
		success: function(data){
			$("#results").append(data);
		}
	});
}

setTimeout("autoRefresh()", time);
</script>