捕捉模型错误的最佳方法？ （Node.js + 续集）

Question

是否有一种简单的方法来捕获使用 Node.js 和 Sequelize（模型）的 API（服务器）中的错误？这是我的代码（它使用 async + await）：

const router = express.Router()
const { Operations } = require('../models')

router.post('/operations/add', async (req, res) => {
    const operations = req.body
    await operations.create(operations)
    res.json(operations)
    console.log('op added!')
})

router.put('/operations/update/:id', async (req, res) => {
    const operationId = req.params.id
    const operationUpdatedData = req.body
    const operationById = await Operation.findOne({ where: { id: operationId } })
    const operationUpdated = await operationById.update(operationUpdatedData)
    res.json(operationUpdated)
    console.log('op updated!')
})

router.delete('/operations/delete/:id', async (req, res) => {
    const operationId = req.params.id
    await Operations.destroy({ where: { id: operationId } })
    res.send('op deleted!')
    console.log('op deleted!')
})

module.exports = router

这是我在客户端处理错误的方式：

axios.post(`http://localhost:9000/operations/add`, data)
            .then(res => console.log(`op added! (${res.status})`))
            .catch(err => console.log(`wrong! (${err.response.status} )`))

我不想要任何花哨的东西，但请随意尝试任何你想要的东西！

Answer 1

如果要处理特定错误，请附加.catch 处理程序

router.post("/operations/add", async (req, res) => {
  try {
    const operations = req.body;
    await operations.create(operations);
    res.json(operations);
    console.log("op added!");
  } catch (error) {
    // handle error here if you want to send on front simply send
    console.log(error)
    res.json(error.message)
  }
});

如果您想更一般地处理错误（即显示一个很好的错误消息，而不是杀死您的服务器，您可能希望查看未处理的异常

https://nodejs.org/api/process.html#process_event_uncaughtexception

如果你使用express，它还包含一些错误处理工具http://expressjs.com/en/guide/error-handling.html