单击画布时获取鼠标坐标

Question

一个常见问题，但我仍然需要帮助。当有人在画布内单击时，我试图获取并存储鼠标坐标。

我的 HTML

<canvas id="puppyCanvas" width="500" height="500" style="border:2px solid black" onclick = "storeGuess(event)"></canvas>

还有我的 javascript

//setup canvas
var canvasSetup = document.getElementById("puppyCanvas");
var ctx = canvasSetup.getContext("2d");

guessX = 0;//stores user's click on canvas
 guessY = 0;//stores user's click on canvas

function storeGuess(event){
    var x = event.clientX - ctx.canvas.offsetLeft;
    var y = event.clientY - ctx.canvas.offsetTop;
    /*guessX = x;
    guessY = y;*/


    console.log("x coords:" + x + ", y coords" + y);

我已经阅读了大量关于此的论坛、w3schools 和视频。我快要弄清楚了，但我错过了一些东西。删除ctx.canvas.offsetLeft和ctx.canvas.offsetTop可以得到页面的坐标。但我需要以某种方式合并这些以获取画布的坐标，然后将其存储到变量guessX 和guessY 中。

Answer 1

您可以通过使用MouseEvent 的offsetX 和offsetY 属性来实现这一点

//setup canvas
var canvasSetup = document.getElementById("puppyCanvas");
var ctx = canvasSetup.getContext("2d");
guessX = 0; //stores user's click on canvas
guessY = 0; //stores user's click on canvas
function storeGuess(event) {
    var x = event.offsetX;
    var y = event.offsetY;
    guessX = x;
    guessY = y;
    console.log("x coords: " + guessX + ", y coords: " + guessY);
}

<canvas id="puppyCanvas" width="500" height="500" style="border:2px solid black" onclick="storeGuess(event)"></canvas>

Answer 2

我正在使用这段代码。

var myCanvas = document.querySelector('#canvas');

myCanvas.addEventListener('click', function(event) {
    var rect = myCanvas.getBoundingClientRect();
    var x = event.clientX - rect.left;
    var y = event.clientY - rect.top;
    console.log("x: " + x + " y: " + y); 
}, false);

<canvas width="400" height="400" id="canvas" style="background-color: lightblue"></canvas>