Spring SpEL JPA @Query - 使用数字列获取“QueryException：并非所有命名参数都已设置”答案

【问题标题】：Spring SpEL JPA @Query - getting "QueryException: Not all named parameters have been set" with numeric columnSpring SpEL JPA @Query - 使用数字列获取“QueryException：并非所有命名参数都已设置”
【发布时间】：2016-08-10 21:08:42
【问题描述】：

我有一个包含两个字段的简单 Person 实体：

@Entity
@Table(name = "person")
public class Person implements Serializable {

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Long id;

    @Column(name = "name", length = 50)
    private String name;

    //setter/getters
}

一个 JpaRepository，我在其中覆盖 findAll 方法以根据用户角色限制记录：

public interface PersonRepository extends JpaRepository<Person,Long> {

    @Query("select p from Person p where p.name like ?#{hasRole('ROLE_ADMIN') ? '%' : principal.username}")
    @Override
    List<Person> findAll();
}

上述设置工作正常。但是当我将查询更新为以下内容时，它会抛出如下异常。看起来它无法解析 SpEL 表达式。

有问题的查询：

@Query("select p from Person p where p.id like ?#{hasRole('ROLE_ADMIN') ? '%' : principal.userId}")

例外：

Caused by: java.lang.IllegalArgumentException: org.hibernate.QueryException: Not all named parameters have been set: [1] [select p from Person p where p.id like ?1]
    at org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1750)
    at org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1677)
    at org.hibernate.jpa.internal.QueryImpl.getResultList(QueryImpl.java:458)
    at org.springframework.data.jpa.repository.query.JpaQueryExecution$CollectionExecution.doExecute(JpaQueryExecution.java:114)
    at org.springframework.data.jpa.repository.query.JpaQueryExecution.execute(JpaQueryExecution.java:78)
    at org.springframework.data.jpa.repository.query.AbstractJpaQuery.doExecute(AbstractJpaQuery.java:100)
    at org.springframework.data.jpa.repository.query.AbstractJpaQuery.execute(AbstractJpaQuery.java:91)
    at org.springframework.data.repository.core.support.RepositoryFactorySupport$QueryExecutorMethodInterceptor.doInvoke(RepositoryFactorySupport.java:462)
    at org.springframework.data.repository.core.support.RepositoryFactorySupport$QueryExecutorMethodInterceptor.invoke(RepositoryFactorySupport.java:440)
    at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:179)
    at org.springframework.data.projection.DefaultMethodInvokingMethodInterceptor.invoke(DefaultMethodInvokingMethodInterceptor.java:61)
    at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:179)
    at org.springframework.transaction.interceptor.TransactionInterceptor$1.proceedWithInvocation(TransactionInterceptor.java:99)
    at org.springframework.transaction.interceptor.TransactionAspectSupport.invokeWithinTransaction(TransactionAspectSupport.java:281)
    at org.springframework.transaction.interceptor.TransactionInterceptor.invoke(TransactionInterceptor.java:96)
    at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:179)
    at org.springframework.dao.support.PersistenceExceptionTranslationInterceptor.invoke(PersistenceExceptionTranslationInterceptor.java:136)
    ... 142 common frames omitted
Caused by: org.hibernate.QueryException: Not all named parameters have been set: [1] [select p from Person p where p.id like ?1]
    at org.hibernate.internal.AbstractQueryImpl.verifyParameters(AbstractQueryImpl.java:401)
    at org.hibernate.internal.AbstractQueryImpl.verifyParameters(AbstractQueryImpl.java:385)
    at org.hibernate.internal.QueryImpl.list(QueryImpl.java:99)
    at org.hibernate.jpa.internal.QueryImpl.list(QueryImpl.java:573)
    at org.hibernate.jpa.internal.QueryImpl.getResultList(QueryImpl.java:449)
    ... 156 common frames omitted

我玩了它并尝试了以下选项，但得到了同样的例外：

1) 用 = 替换 LIKE

@Query("select p from Person p where p.id = ?#{hasRole('ROLE_ADMIN') ? '1' : principal.userId}")

2) 设置硬编码 id：

@Query("select p from Person p where p.id = ?#{hasRole('ROLE_ADMIN') ? '6' : '5'}")

有什么建议吗？

仅供参考：

我的 pom.xml 中有 spring boot 1.3.6.RELEASE、hibernate 4.3.11.Final。
我已正确配置/覆盖 org.springframework.security.core.userdetails.User 对象传递用户 ID。

【问题讨论】：

标签： java spring hibernate spring-data-jpa spring-el

【解决方案1】：

我不确定 SpEL 解析器和 Spring Data JPA 之间是否存在冲突。但我找到了解决方法：

解决方案： @Query 上的以下更改效果很好：

@Query("select p from Person p where p.id = ?#{principal.customerId} or 1=?#{hasRole('ROLE_ADMIN') ? 1 : 0}")

【讨论】：