【发布时间】:2017-05-04 00:52:05
【问题描述】:
在为专辑选择应用程序获取简单过滤器时遇到问题,我正在为使用 jsonplaceholderdata 体验而构建。我尝试将 ng-model 设置为表达式并按该表达式进行过滤,但是当我在输入栏中输入文本时没有任何变化。不确定我错过了什么。
<!DOCTYPE html>
<html>
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<head>
<script src = "https://ajax.googleapis.com/ajax/libs/angularjs/1.6.4/angular.min.js"></script>
<script type="text/javascript" src="album.js"></script>
<link rel="stylesheet" href="bootstrap/css/bootstrap.min.css">
<link rel="stylesheet" href="album.css">
</head>
<body>
<div class="bar">
<input type="text" class="search" ng-model="q" placeholder="Enter your search terms" />
<button ng-click="search(q)">Search</button>
</div>
<div ng-app="myApp" ng-controller="AlbumCtrl">
<div ng-click="showme = !showme" ng-init="count=0" ng-repeat="album in albumData|filter:q" id="thumbWrapper">
<h1>{{album.id}}</h1>
<p>{{album.title}}</p>
<div id="thumbList"ng-show="showme"class="albumContent">
<ul ng-controller="PhotoCtrl" id="thumbList">
<li ng-repeat="photo in photoData" ng-if="album.userId == photo.albumId">
<img ng-src={{photo.url}}>
</li>
</ul>
</div>
</div>
</div>
这是我的 Angular js 代码:
var app = angular.module('myApp', []);
app.controller('AlbumCtrl', function ($scope, $http) {
$http.get("http://jsonplaceholder.typicode.com/albums").then(function(response) {
$scope.albumData = response.data;
console.log($scope.albumData);
});
});
app.controller('PhotoCtrl', function($scope, $http) {
$http.get("http://jsonplaceholder.typicode.com/photos").then(function(response) {
$scope.photoData = response.data;
// console.log($scope.photoData);
});
});
非常感谢任何帮助。
【问题讨论】:
标签: angularjs html angularjs-filter