【问题标题】:Spring batch job repository tables are not getting created in the schema I configuredSpring 批处理作业存储库表未在我配置的架构中创建
【发布时间】:2019-12-18 19:29:09
【问题描述】:

我遇到了类似的问题。我有 2 个数据源,主数据源和第二个数据源应该由 Spring Batch 使用。 spring batch 正在主数据源中创建模式并尝试在第二个中插入/更新这是我的代码:

异常:java.sql.SQLSyntaxErrorException:用户缺少权限或找不到对象:语句 [SELECT JOB_INSTANCE_ID, JOB_NAME from BATCH_JOB_INSTANCE where JOB_NAME = 中的 BATCH_JOB_INSTANCE和 JOB_KEY = ?]

public class DataSourceConfig {
@Bean
@Primary
@ConfigurationProperties("spring.datasource")
public DataSourceProperties primaryDataSourceProperties() {
    return new DataSourceProperties();
}

@Bean("secondDataSourceProperties")
@ConfigurationProperties("spring.second-datasource")
public DataSourceProperties secondDataSourceProperties() {
    return new DataSourceProperties();
}

/**
 * Create primary (default) DataSource.
 */
@Bean
@Primary
public DataSource primaryDataSource(@Autowired DataSourceProperties props) {
    return props.initializeDataSourceBuilder().build();
}

/**
 * Create second DataSource and named "secondDatasource".
 */
@Bean("secondDatasource")
public DataSource secondDataSource(@Autowired 
@Qualifier("secondDataSourceProperties") DataSourceProperties props) {
    return props.initializeDataSourceBuilder().build();
}
}

@Component
@Configuration
public class MyBatchConfigurer extends DefaultBatchConfigurer {

/**
 * Initialize the BatchConfigurer to use the datasource of your choosing
 *
 * @param secondDatasource
 */

@Autowired
@Qualifier("secondDatasource")
DataSource datasource;

@Override
protected JobRepository createJobRepository() throws Exception {
    JobRepositoryFactoryBean factory = new JobRepositoryFactoryBean();
    factory.setDataSource(datasource);
    factory.setTransactionManager(transactionManager());
    factory.afterPropertiesSet();

    return factory.getObject();
}

private PlatformTransactionManager transactionManager() {
    return new DataSourceTransactionManager(datasource);
}
}

【问题讨论】:

  • 欢迎来到 StackOverflow!错误消息对我来说并不模棱两可。您是否已经检查了用户权限和表的存在?
  • 是的,我做到了。未创建表
  • spring batch is creating the schema in the primary data source 这是不正确的。 Spring Batch 不创建表。应该是 Spring Boot。因此,请确保在 Spring Batch 配置中使用由 spring Boot 初始化的相同数据源。

标签: java spring spring-boot spring-batch


【解决方案1】:

创建BatchConfigurer 的自定义实现。

import javax.annotation.PostConstruct;
import javax.sql.DataSource;
import org.springframework.batch.core.configuration.BatchConfigurationException;
import org.springframework.batch.core.explore.JobExplorer;
import org.springframework.batch.core.explore.support.JobExplorerFactoryBean;
import org.springframework.batch.core.explore.support.MapJobExplorerFactoryBean;
import org.springframework.batch.core.launch.JobLauncher;
import org.springframework.batch.core.launch.support.SimpleJobLauncher;
import org.springframework.batch.core.repository.JobRepository;
import org.springframework.batch.core.repository.support.JobRepositoryFactoryBean;
import org.springframework.batch.core.repository.support.MapJobRepositoryFactoryBean;
import org.springframework.batch.support.transaction.ResourcelessTransactionManager;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.jdbc.datasource.DataSourceTransactionManager;
import org.springframework.stereotype.Component;
import org.springframework.transaction.PlatformTransactionManager;

@Component
public class MyBatchConfigurer implements BatchConfigurer {


    private PlatformTransactionManager transactionManager;
    private JobRepository jobRepository;
    private JobLauncher jobLauncher;
    private JobExplorer jobExplorer;
    @Autowired
    @Qualifier("secondDatasource")
    private DataSource dataSource;

    @Override
    public JobRepository getJobRepository() {
        return jobRepository;
    }

    @Override
    public PlatformTransactionManager getTransactionManager() {
        return new DataSourceTransactionManager(datasource);
    }

    @Override
    public JobLauncher getJobLauncher() {
        return jobLauncher;
    }

    @Override
    public JobExplorer getJobExplorer() {
        return jobExplorer;
    }

    @PostConstruct
    public void initialize() {
        try {
            this.jobRepository = createJobRepository();
            this.jobExplorer = createJobExplorer();
            this.jobLauncher = createJobLauncher();
        } catch (Exception e) {
            throw new BatchConfigurationException(e);
        }
    }

    protected JobLauncher createJobLauncher() throws Exception {
        SimpleJobLauncher jobLauncher = new SimpleJobLauncher();
        jobLauncher.setJobRepository(jobRepository);
        jobLauncher.afterPropertiesSet();
        return jobLauncher;
    }

    protected JobRepository createJobRepository() throws Exception {
        JobRepositoryFactoryBean factory = new JobRepositoryFactoryBean();
        factory.setDataSource(datasource);
        factory.setTransactionManager(transactionManager());
        factory.afterPropertiesSet();

        return factory.getObject();
    }

    protected JobExplorer createJobExplorer() throws Exception {
        JobExplorerFactoryBean jobExplorerFactoryBean = new JobExplorerFactoryBean();
        jobExplorerFactoryBean.setDataSource(this.dataSource);
        jobExplorerFactoryBean.afterPropertiesSet();
        return jobExplorerFactoryBean.getObject();
    }
}

【讨论】:

    【解决方案2】:

    这就是我为使它工作所做的事情 我刚刚添加了一个注入第二个数据源的 bean。

    @Bean
    BatchConfigurer configurer(@Autowired @Qualifier("secondDatasource") DataSource dataSource) {
        return new DefaultBatchConfigurer(dataSource);
    }
    

    但仍然没有创建架构 我用过:

    @Configuration
    @Profile({"dev","prod"})
    public class JobRepositorySchemaConfig {
    private final String JOB_REPO_SCHEMA = "classpath:batch_repo_schema.sql";
    
    @Autowired
    @Qualifier("secondDatasource")
    DataSource datasource;
    
    @Autowired
    WebApplicationContext webApplicationContext;
    
    @PostConstruct
    public void loadIfInMemory() throws Exception {
        Resource resource = webApplicationContext.getResource("classpath:/org/springframework/batch/core/schema-drop-hsqldb.sql");
        Resource resource2 = webApplicationContext.getResource("classpath:/org/springframework/batch/core/schema-hsqldb.sql");
        ScriptUtils.executeSqlScript(datasource.getConnection(), resource);
        ScriptUtils.executeSqlScript(datasource.getConnection(), resource2);
    }
    

    }

    【讨论】:

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