Java Spring Boot 无法从值为 hashmap 的键中读取结果

Question

我有一个简单的服务器从 mongodb 读取所有日志，但是 db 中的某些数据的结果属性具有不同的格式。

其中一个结果属性的值类似于哈希图：

{
    "event_name" : "Transfer", 
    "result" : { "_from" : "0x928c9af0651632157ef27a2cf17ca72c575a4d21", 
                   "_value" : "1111", 
                 "_to"  :"0x143449e55cdd2a5bae081f041650ba9089812a95" },  

 "transaction_id":"c2c986a96a0cfa7fc96619733449fd88c9d685bf704a50d07baef74f6
}

那么对于 result 属性，它会为我返回一个空结果， 但是如果结果属性是这样的，就像一个数组：

"result" : ["0x928c9af0651632157ef27a2cf17ca72c575a4d21",  "1111", "0x143449e55cdd2a5bae081f041650ba9089812a95"],

然后它会输出结果值。 问题是它在 mongodb 中同时具有两种格式，有什么方法可以同时处理这两种不同格式的结果属性？

import com.alibaba.fastjson.JSONArray;
import com.fasterxml.jackson.annotation.JsonProperty;
import java.io.Serializable;
import org.springframework.data.annotation.Id;
import org.springframework.data.mongodb.core.mapping.Document;
import org.springframework.data.mongodb.core.mapping.Field;

@Document(collection = "eventLog")
public class EventLogEntity implements Serializable {

  private static final long serialVersionUID = -70777625567836430L;

  @Id
  private String id;

  @Field(value = "block_number")
  @JsonProperty(value = "block_number")
  private long blockNumber;

  @Field(value = "block_timestamp")
  @JsonProperty(value = "block_timestamp")
  private long blockTimestamp;

  @Field(value = "contract_address")
  @JsonProperty(value = "contract_address")
  private String contractAddress;

  @Field(value = "event_name")
  @JsonProperty(value = "event_name")
  private String entryName;

  @Field(value = "result")
  @JsonProperty(value = "result")
  private JSONArray resultJsonArray;

  @Field(value = "transaction_id")
  @JsonProperty(value = "transaction_id")
  private String transactionId;

  public EventLogEntity(long blockNumber, long blockTimestamp, String contractAddress,
      String entryName, JSONArray resultJsonArray, String transactionId) {
    this.blockNumber = blockNumber;
    this.blockTimestamp = blockTimestamp;
    this.contractAddress = contractAddress;
    this.entryName = entryName;
    this.resultJsonArray = resultJsonArray;
    this.transactionId = transactionId;
  }

  public static long getSerialVersionUID() {
    return serialVersionUID;
  }

  public long getBlockNumber() {
    return blockNumber;
  }

  public void setBlockNumber(long blockNumber) {
    this.blockNumber = blockNumber;
  }

  public long getBlockTimestamp() {
    return blockTimestamp;
  }

  public void setBlockTimestamp(long blockTimestamp) {
    this.blockTimestamp = blockTimestamp;
  }

  public String getContractAddress() {
    return contractAddress;
  }

  public void setContractAddress(String contractAddress) {
    this.contractAddress = contractAddress;
  }

  public String getEntryName() {
    return entryName;
  }

  public void setEntryName(String entryName) {
    this.entryName = entryName;
  }

  public JSONArray getResultJsonArray() {
    System.out.println(resultJsonArray.toString());
    return resultJsonArray;
  }

  public void setResultJsonArray(JSONArray resultJsonArray) {
    this.resultJsonArray = resultJsonArray;
  }

  public String getTransactionId() {
    return transactionId;
  }

  public void setTransactionId(String transactionId) {
    this.transactionId = transactionId;
  }
}

Answer 1

首先，您有 2 个不同的文档实体，如果您确实需要保留两种格式并阅读其中一种，则每个结构都应该有一个实体。 一个实体将如您所描述的那样，另一个将具有如下结果属性：

public class ResultObject{
   private String _from;
   private String _value;
   private String _to;

   //getters, setters & constructor
}

并且您将此 ResultObject 引用为其他实体的属性：

public class EventLogEntityWithResultObject implements Serializable{
...
private ResultObject result;
...
}

如果您不需要保留这两种结构，您可以使用 MongoDB 命令将所有文档从一种结构类型迁移到另一种结构类型，例如：Change document structure in mongodb with the mongo shell