如何在 2 个 int 函数之间重复抛出一个变量？

Question

我正在尝试创建一个执行以下操作的程序：
公交车每次停靠，都要装卸乘客。每个公交车站下车的乘客数量必须随机生成。每个站点的候车人数也是随机生成的。公共汽车应在不超过公共汽车容量的情况下装载尽可能多的等候乘客。

#include <iostream>
#include <ctime>
#include <cstdlib>
#include <iomanip>
using namespace std;

void stop_bus(int); /* Stop the bus */ 
int unload_pass(int); /* Unload passengers */ 
int load_pass(int); /* Load passengers */ 
void start_bus(); /* Start the bus */


int main()
{
    srand(time(0));
    int stops = 7, currentStop = 1;
    int maxPass = 50;

    load_pass(maxPass);
    while(currentStop < stops)
    {
        currentStop++;
        stop_bus(currentStop); 
        unload_pass(maxPass); 
        load_pass(maxPass); 
        //start_bus(); 
    }


    system("pause");
    return 0;
}
void stop_bus(int currentStop)
{
    cout << "Currently at stop #" << currentStop << endl;
    cout << "Please disembark the bus in an orderly fashion." << endl;
    cout << endl;
}
int unload_pass(int maxPass)
{
    int passOff;
    int currentPass;
    currentPass = load_pass(maxPass);

    passOff = 1 + rand() % 50;
    while (currentPass - passOff > 0 )
    {
        cout << currentPass << ": That number is not in the range." << endl;
        passOff = 1 + rand() % 50;
        cout << endl;
    }

    cout << "People leaving the bus: " << passOff << endl;
    currentPass = currentPass - passOff;
    cout << "Current bus load is " << currentPass << endl;
    cout << endl;
    cout << currentPass << ": That number is not in the range" << endl;
    cout << endl;
    return currentPass;
}
int load_pass(int maxPass)
{
    int passOn;
    int currentPass;
    currentPass = unload_pass(maxPass);

    passOn = 1 + rand() % 50;
    while (currentPass + passOn > maxPass)
    {
        cout << currentPass << ": That number is not in the range" << endl;
        passOn = 1 + rand() % 50;
        cout << endl;
    }
    cout << "People boarding the bus: " << passOn << endl;
    currentPass = currentPass + passOn;
    cout << "Current bus load is "  << currentPass << endl;
    cout << endl;
    return currentPass;
}

我很肯定我做错了。当我尝试运行它时，会弹出另一个窗口告诉我破解代码。这究竟是什么意思，我该如何解决？

Answer 1

消息到底说了什么？如果“break”在这种情况下意味着“停止”，那么你可能有一个无限循环。通过检查您的代码，看起来 load_pass() 以调用 unload_pass() 开始，而 unload_pass() 又以再次调用 load_pass() 开始。

这本质上是一个无限递归，很可能会导致您看到的错误。

您是否看到打印语句的任何输出？那将是另一个很好的线索。

Answer 2

看这里：

int unload_pass(int maxPass)
{
    int passOff;
    int currentPass;
    currentPass = load_pass(maxPass);

和

int load_pass(int maxPass)
{
    int passOn;
    int currentPass;
    currentPass = unload_pass(maxPass);

这两个函数相互调用，直到堆栈溢出。

要找出问题所在，在调试器中运行代码、观察调用堆栈、检查变量值等。