【发布时间】:2015-07-09 13:05:44
【问题描述】:
我使用过滤器检查登录用户的 URL 模式。
但我有许多 URL 模式需要过滤。
{ "/table/*", "/user/*", "/contact/*", "/run/*", "/conf/*", ..., ..., ...}
它变得无法维护。排除会更简单:
{ "/", "/login", "/logout", "/register" }
我怎样才能做到这一点?
@WebFilter(urlPatterns = { "/table/*","/user/*", "/contact/*","/run/*","/conf/*"})
public class SessionTimeoutRedirect implements Filter {
protected final Logger logger = LoggerFactory.getLogger("SessionFilter");
@Override
public void doFilter(ServletRequest req, ServletResponse res,
FilterChain chain) throws IOException, ServletException {
HttpServletRequest request = (HttpServletRequest) req;
HttpServletResponse response = (HttpServletResponse) res;
if (request.getSession().getAttribute("Id") != null) {
chain.doFilter(req, res);
} else {
logger.debug("session is null:"+request.getRequestURL());
response.sendRedirect(request.getContextPath()+"/login");
}
}
@Override
public void init(FilterConfig arg0) throws ServletException {
}
@Override
public void destroy() {
}
}
【问题讨论】:
标签: java servlets servlet-filters url-pattern