【问题标题】:Is it possible to back a readonly SQLite database with a memory buffer (or PE resource)?是否可以使用内存缓冲区(或 PE 资源)支持只读 SQLite 数据库?
【发布时间】:2012-05-04 01:14:13
【问题描述】:

我想使用 Windows 的“自定义资源”功能将存储在 SQLite 数据库中的相当大的数据块嵌入到我的二进制文件中。 (这是日志工具的白名单)SQLite 确实支持in memory databases,但看起来可能仅限于创建全新的数据库;并且似乎不支持从内存缓冲区中读取;但我并不积极。

数据库是否支持这样的东西? (由于其他原因,我必须嵌入 SQLite,所以将它用于白名单也很棒......)

【问题讨论】:

  • 我没有你的问题的答案。我确实有解决您问题的方法:将 sql 命令存储在资源中,然后将该脚本传递给 SQLite 引擎。
  • @Robᵩ:是的,这会起作用,但如果这样做了,我就不能预先生成索引或其他类似的东西并嵌入它们——它们必须在运行中完成,这将是昂贵的. (使用 SQLite 而不是像协议缓冲区这样的通用序列化工具的一半是为了更容易嵌入预生成的索引)

标签: c++ c windows sqlite


【解决方案1】:

sqlite 文档http://www.sqlite.org/backup.html 的在线备份部分有一些代码可以执行您想要的操作(例如,将内存数据库中的转储到文件,或将文件重新加载到内存数据库中)。这应该允许您将预先索引的数据库保存到一个文件中,您可以将其添加到资源中并在运行时加载到内存中。

这是有问题的代码(直接从上面链接的页面复制)

/*
** This function is used to load the contents of a database file on disk 
** into the "main" database of open database connection pInMemory, or
** to save the current contents of the database opened by pInMemory into
** a database file on disk. pInMemory is probably an in-memory database, 
** but this function will also work fine if it is not.
**
** Parameter zFilename points to a nul-terminated string containing the
** name of the database file on disk to load from or save to. If parameter
** isSave is non-zero, then the contents of the file zFilename are 
** overwritten with the contents of the database opened by pInMemory. If
** parameter isSave is zero, then the contents of the database opened by
** pInMemory are replaced by data loaded from the file zFilename.
**
** If the operation is successful, SQLITE_OK is returned. Otherwise, if
** an error occurs, an SQLite error code is returned.
*/
int loadOrSaveDb(sqlite3 *pInMemory, const char *zFilename, int isSave){
  int rc;                   /* Function return code */
  sqlite3 *pFile;           /* Database connection opened on zFilename */
  sqlite3_backup *pBackup;  /* Backup object used to copy data */
  sqlite3 *pTo;             /* Database to copy to (pFile or pInMemory) */
  sqlite3 *pFrom;           /* Database to copy from (pFile or pInMemory) */

  /* Open the database file identified by zFilename. Exit early if this fails
  ** for any reason. */
  rc = sqlite3_open(zFilename, &pFile);
  if( rc==SQLITE_OK ){

    /* If this is a 'load' operation (isSave==0), then data is copied
    ** from the database file just opened to database pInMemory. 
    ** Otherwise, if this is a 'save' operation (isSave==1), then data
    ** is copied from pInMemory to pFile.  Set the variables pFrom and
    ** pTo accordingly. */
    pFrom = (isSave ? pInMemory : pFile);
    pTo   = (isSave ? pFile     : pInMemory);

    /* Set up the backup procedure to copy from the "main" database of 
    ** connection pFile to the main database of connection pInMemory.
    ** If something goes wrong, pBackup will be set to NULL and an error
    ** code and  message left in connection pTo.
    **
    ** If the backup object is successfully created, call backup_step()
    ** to copy data from pFile to pInMemory. Then call backup_finish()
    ** to release resources associated with the pBackup object.  If an
    ** error occurred, then  an error code and message will be left in
    ** connection pTo. If no error occurred, then the error code belonging
    ** to pTo is set to SQLITE_OK.
    */
    pBackup = sqlite3_backup_init(pTo, "main", pFrom, "main");
    if( pBackup ){
      (void)sqlite3_backup_step(pBackup, -1);
      (void)sqlite3_backup_finish(pBackup);
    }
    rc = sqlite3_errcode(pTo);
  }

  /* Close the database connection opened on database file zFilename
  ** and return the result of this function. */
  (void)sqlite3_close(pFile);
  return rc;
}

【讨论】:

  • 这是一个有趣的信息块,但根本没有解决原始问题。 OP 已经导出了他们的数据库,它正在重新打开它,这就是问题所在。他们在内存中有一个缓冲区,而不是在文件中,他们想直接打开。备份 API 可让您复制到数据库(因此他们可以使用空白内存数据库作为目标),但源也必须是开放数据库。这是一个陷阱 22:要访问包含所有数据的开放数据库,他们必须已经解决了他们的问题!
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