Spring AOP 事务 - 基于属性的超时？

Question

在处理 Spring Transactions/AOP 时，我可以使用 Spring EL 从属性文件中提取超时值并将其转换为整数吗？

这里是代码

<tx:advice id="GlobalDataTxAdvice" transaction-manager="GlobalDataTransactionManager">
    <tx:attributes>
        <tx:method name="get*" no-rollback-for="javax.persistence.NoResultException,javax.persistence.NonUniqueResultException,org.springframework.dao.EmptyResultDataAccessException"/>
        <tx:method name="find*" no-rollback-for="javax.persistence.NoResultException,javax.persistence.NonUniqueResultException,org.springframework.dao.EmptyResultDataAccessException"/>
        <tx:method name="search*" read-only="true" no-rollback-for="javax.persistence.NoResultException,javax.persistence.NonUniqueResultException,org.springframework.dao.EmptyResultDataAccessException"/>
        <tx:method name="*" timeout="${service.jta.timeout:60}"/>
    </tx:attributes>
</tx:advice>

所以我希望默认事务超时为 60 秒，或者允许从属性占位符文件中提取超时（int 值）。

但是当我部署它时，我得到：

weblogic.application.ModuleException: :org.xml.sax.SAXParseException:cvc-datatype-valid.1.2.1: '${service.jta.timeout:60}' 不是 'integer' 的有效值。

Answer 1

试试这个

<util:properties id="contextProperties" location="classpath:context.properties"/>

<tx:advice id="GlobalDataTxAdvice" transaction-manager="GlobalDataTransactionManager">
  <tx:attributes>
    <tx:method name="get*" no-rollback-for="javax.persistence.NoResultException,javax.persistence.NonUniqueResultException,org.springframework.dao.EmptyResultDataAccessException"/>
    <tx:method name="find*" no-rollback-for="javax.persistence.NoResultException,javax.persistence.NonUniqueResultException,org.springframework.dao.EmptyResultDataAccessException"/>
    <tx:method name="search*" read-only="true" no-rollback-for="javax.persistence.NoResultException,javax.persistence.NonUniqueResultException,org.springframework.dao.EmptyResultDataAccessException"/>
    <tx:method name="*" timeout="#{ T(Integer).valueOf(contextProperties['timeout']?: 60)}"/>
  </tx:attributes>
</tx:advice>

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