如果数据库（oracle）中没有记录结合使用spring jpa的日期列，如何将零显示为计数？

Question

我想按小时查询表中列值在当天的事务计数，因为我想在图表中显示这些计数。

即使在没有记录的几个小时内我也无法显示结果，在这种情况下我应该打印 0 个计数，我已经尝试过

with tmpTable as 
(
    select 
        (minHourSeq + level-1) hourSeq 
    from 
        (select 
             min(extract (hour from TXN_DATE_TIME)) minHourSeq, 
             max(extract (hour from TXN_DATE_TIME)) maxHourSeq 
         from 
             TRANSACTION_REQUEST) v 
    connect by 
        (minHourSeq + level-1) <= maxHourSeq
)
select 
    a.hourSeq as hour, nvl(count(b.transaction), 0) as count 
from 
    TRANSACTION_REQUEST b, tmpTable a 
where 
    a.hourSeq = extract(hour from b.TXN_DATE_TIME(+)) 
group by 
    a.hourSeq 
order by 
    1;

当我在 Oracle SQL 开发人员中执行它时它正在工作，但是我收到一个错误

ORA-00907: 缺少右括号

在尝试使用我的代码实现时

Query query = entityManager.createNativeQuery(
                "with tmpTable as (select (minHourSeq + level-1) hourSeq from (select min(extract (hour from txnDate)) minHourSeq, max(extract (hour from txnDate)) maxHourSeq from "
                        + TransactionRequest.class.getName()
                        + " ) v connect by (minHourSeq + level-1) <= maxHourSeq) "
                        + "select a.hourSeq as hour,nvl(count(b.transaction),0) as count from "
                        + TransactionRequest.class.getName()
                        + " b,tmpTable a a.hourSeq = extract(hour from b.txnDate(+)) group by a.hourSeq order by 1"); 

Answer 1

“其他解决方案”可能会将 CTE 移动到内联视图中；也许您使用的工具无法识别它。像这样的：

  SELECT a.hourSeq AS hour, NVL (COUNT (b.transaction), 0) AS COUNT
    FROM TRANSACTION_REQUEST b,
         -- WITH factoring clause moved into an inline view
         (    SELECT (minHourSeq + LEVEL - 1) hourSeq
                FROM (SELECT MIN (EXTRACT (HOUR FROM TXN_DATE_TIME)) minHourSeq,
                             MAX (EXTRACT (HOUR FROM TXN_DATE_TIME)) maxHourSeq
                        FROM TRANSACTION_REQUEST) v
          CONNECT BY (minHourSeq + LEVEL - 1) <= maxHourSeq) a
   WHERE a.hourSeq = EXTRACT (HOUR FROM b.TXN_DATE_TIME(+))
GROUP BY a.hourSeq
ORDER BY 1;

Answer 2

你在query 的值中错过了where，使用这个：

Query query = entityManager.createNativeQuery(
                "with tmpTable as (select (minHourSeq + level-1) hourSeq from (select min(extract (hour from txnDate)) minHourSeq, max(extract (hour from txnDate)) maxHourSeq from "
                        + TransactionRequest.class.getName()
                        + " ) v connect by (minHourSeq + level-1) <= maxHourSeq) "
                        + "select a.hourSeq as hour,nvl(count(b.transaction),0) as count from "
                        + TransactionRequest.class.getName()
                        + " b,tmpTable a where a.hourSeq = extract(hour from b.txnDate(+)) group by a.hourSeq order by 1");