【发布时间】:2012-03-07 16:04:58
【问题描述】:
我在不知道 Heroku 需要 Postgresql 的情况下使用 Rails 开始了一个项目。现在我想将我的 sqlite3 表转换为 postgresql 表。我该怎么做?
我找到了一种获取 SQL 插入的方法:
BEGIN TRANSACTION;
insert into places ("id", "name", "content", "tags", "created_at", "updated_at") values ('0', 'bac à papier', NULL, 'bac de recyclage', '13309980782012-03-06 03:57:21.219233', '13309980782012-03-06 03:57:21.219233');
insert into places ("id", "name", "content", "tags", "created_at", "updated_at") values ('1', 'bac PVM', 'plastique/verre/métal', NULL, '13310076572012-03-06 03:57:21.219233', '13310076572012-03-06 03:57:21.219233');
insert into places ("id", "name", "content", "tags", "created_at", "updated_at") values ('2', 'bac de déchets', NULL, 'poubelle', '13310076572012-03-06 03:57:21.219233', '13310076572012-03-06 03:57:21.219233');
insert into places ("id", "name", "content", "tags", "created_at", "updated_at") values ('3', 'cafétéria', '', '', '2012-03-06 03:57:21.219233', '2012-03-06 03:57:21.219233');
insert into places ("id", "name", "content", "tags", "created_at", "updated_at") values ('4', 'compost', NULL, NULL, '2012-03-06 03:57:21.219233', '2012-03-06 03:57:21.219233');
insert into places ("id", "name", "content", "tags", "created_at", "updated_at") values ('5', 'consigne', NULL, NULL, '2012-03-06 03:57:21.219233', '2012-03-06 03:57:21.219233');
insert into places ("id", "name", "content", "tags", "created_at", "updated_at") values ('6', 'CRD', NULL, NULL, '2012-03-06 03:57:21.219233', '2012-03-06 03:57:21.219233');
insert into places ("id", "name", "content", "tags", "created_at", "updated_at") values ('7', 'ressources matérielles', NULL, NULL, '2012-03-06 03:57:21.219233', '2012-03-06 03:57:21.219233');
insert into places ("id", "name", "content", "tags", "created_at", "updated_at") values ('8', 'sécurité', NULL, NULL, '2012-03-06 03:57:21.219233', '2012-03-06 03:57:21.219233');
insert into places ("id", "name", "content", "tags", "created_at", "updated_at") values ('10', 'technicien chimie', NULL, NULL, '2012-03-06 03:57:21.219233', '2012-03-06 03:57:21.219233');
insert into places ("id", "name", "content", "tags", "created_at", "updated_at") values ('11', 'technicien biologie', NULL, NULL, '2012-03-06 03:57:21.219233', '2012-03-06 03:57:21.219233');
insert into places ("id", "name", "content", "tags", "created_at", "updated_at") values ('12', 'service informatique', NULL, NULL, '2012-03-06 03:57:21.219233', '2012-03-06 03:57:21.219233');
insert into places ("id", "name", "content", "tags", "created_at", "updated_at") values ('13', 'îlot multi-récupération', 'face au B-227', NULL, '2012-03-06 03:57:21.219233', '2012-03-06 03:57:21.219233');
insert into places ("id", "name", "content", "tags", "created_at", "updated_at") values ('14', 'récupérateurs extérieurs', NULL, NULL, '2012-03-06 03:57:21.219233', '2012-03-06 03:57:21.219233');
COMMIT;
解决方案 这是我解决问题的方法:
我使用 Chris 的解决方案告诉 rails 我想使用 PostgreSQL。然后,我跑了db:migrate。
为了将我的 SQLite 表转换为 PostgreSQL 表,我使用了 Sliteman,这是一个用于管理 SQLite 数据库的 Linux 程序。使用此实用程序,我能够将表转换为 SQL 插入。我登录到 PostgreSQL 并应用了插入。
瞧!
【问题讨论】: