如何只打印自定义异常的痕迹？而是 TestNG Trace [重复]

Question

class use extends Test {

    @org.testng.annotations.Test
    public void test() throws exc {
        try {
            System.out.println("test");
            int a = 1 / 0;
            System.out.println(a);
        } catch (ArithmeticException e) {
            throw new exc("This is EXC error");
        }
    }       

class exc extends Exception {
    private static final long serialVersionUID = 1L;
    public exc(String a) {
        super(a);
    }
}

---

1. 我只想在控制台中打印第一两行
2. 如果我从 Main Method 执行，则可以这样做，但使用 TestNG 会引发额外的跟踪，如图所示。

---

这是控制台

FAILED: test

runner.exc: This is EXC error
    at runner.use.test(Test.java:47)

---

我想打印到这里，但控制台也显示以下内容

at java.base/jdk.internal.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at java.base/jdk.internal.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:64)
at java.base/jdk.internal.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.base/java.lang.reflect.Method.invoke(Method.java:564)
at org.testng.internal.MethodInvocationHelper.invokeMethod(MethodInvocationHelper.java:133)
at org.testng.internal.TestInvoker.invokeMethod(TestInvoker.java:598)
at org.testng.internal.TestInvoker.invokeTestMethod(TestInvoker.java:173)
at org.testng.internal.MethodRunner.runInSequence(MethodRunner.java:46)
at org.testng.internal.TestInvoker$MethodInvocationAgent.invoke(TestInvoker.java:824)
at org.testng.internal.TestInvoker.invokeTestMethods(TestInvoker.java:146)
at org.testng.internal.TestMethodWorker.invokeTestMethods(TestMethodWorker.java:146)
at org.testng.internal.TestMethodWorker.run(TestMethodWorker.java:128)
at java.base/java.util.ArrayList.forEach(ArrayList.java:1511)
at org.testng.TestRunner.privateRun(TestRunner.java:794)
at org.testng.TestRunner.run(TestRunner.java:596)
at org.testng.SuiteRunner.runTest(SuiteRunner.java:377)
at org.testng.SuiteRunner.runSequentially(SuiteRunner.java:371)
at org.testng.SuiteRunner.privateRun(SuiteRunner.java:332)
at org.testng.SuiteRunner.run(SuiteRunner.java:276)
at org.testng.SuiteRunnerWorker.runSuite(SuiteRunnerWorker.java:53)
at org.testng.SuiteRunnerWorker.run(SuiteRunnerWorker.java:96)
at org.testng.TestNG.runSuitesSequentially(TestNG.java:1212)
at org.testng.TestNG.runSuitesLocally(TestNG.java:1134)
at org.testng.TestNG.runSuites(TestNG.java:1063)
at org.testng.TestNG.run(TestNG.java:1031)
at org.testng.remote.AbstractRemoteTestNG.run(AbstractRemoteTestNG.java:115)
at org.testng.remote.RemoteTestNG.initAndRun(RemoteTestNG.java:251)
at org.testng.remote.RemoteTestNG.main(RemoteTestNG.java:77)

Answer 1

您可以使用此代码将前两行作为字符串获取：

// tr is the exception object
StringWriter sw = new StringWriter();
PrintWriter pw = new PrintWriter(sw);
tr.printStackTrace(pw); // Replace tr with your exception object
String[] stl = sw.toString().split("\n");

// Get the first two lines
// Use deleteCharAt(sb.length() - 1) to get rid of \r at the end of the line (You may not need to this)
StringBuilder sb = new StringBuilder();
if (stl.length > 0) sb.append(stl[0]).deleteCharAt(sb.length() - 1).append('\n');
if (stl.length > 1) sb.append(stl[1]).deleteCharAt(sb.length() - 1).append('\n');

// Use sb.toString() to get the result