正则表达式匹配句尾标记[关闭]

Question

我需要匹配给定正文中的所有句尾符号，例如 !、?、.（句点）等。

谁能帮我用正则表达式来做这样的事情？

示例输入：

This is the f!!rst sentence! Is this the second one? The third sentence is here... And the fourth one!!

输出：

This is the f!!rst sentence Is this the second one The third sentence is here And the fourth one

Answer 1

[!?.]+(?=$|\s)

试试这个。你可以根据需要添加标记。替换为``。

查看演示。

http://regex101.com/r/lS5tT3/15

Answer 2

您可能想要匹配任何内容 (.*?)，然后是句末，然后是空格 (\s+)。自从 ！， ？和 。是特殊字符，您需要将它们排除在外。

例如

Pattern pattern = Pattern.compile("(.*?)[\\!\\?\\.]\\s+");
Matcher matcher = pattern.matcher("one two. three! four five? ");
while (matcher.find()) {
   System.out.println(matcher.group(1));
}

打印

one two
three
four five

Answer 3

下面的正则表达式将匹配非单词字符（空格除外），这些字符必须后跟空格字符或行尾锚。 replaceAll 函数有助于删除所有匹配的字符。

String s = "Blah! blah? blah... blah blah!!";
System.out.println(s.replaceAll("[^\\w\\s]+(?=\\s|$)", ""));

输出：

Blah blah blah blah blah

如果您只想删除单词最后出现的?、.、! 字符，您可以尝试以下代码。

String s = "This is the f!!rst sentence! Is this the second one? The third sentence is here... And the fourth one!!";
System.out.println(s.replaceAll("[!?.]+(?=\\s|$)", ""));

输出：

This is the f!!rst sentence Is this the second one The third sentence is here And the fourth one