【发布时间】:2013-06-15 04:23:49
【问题描述】:
我的代码是
#Opens template for creating final report
excel = win32.dynamic.Dispatch('Excel.Application')
template = os.path.abspath((folderpath+'\Poop.xlsx'))
wb = excel.Workbooks.Open(template)
freshws= wb.Sheets("Fresh") #Sheet names must match perfectly
secws= wb.Sheets("sec")
cur.execute("Select * from FIRALL")
freshdata=list(cur.fetchall())
#writes to the first sheet
datarowlen=0
for i,a in enumerate(freshdata):
datarowlen = len(a)
for j,b in enumerate(a):
freshws.Cells(i+1,j+1).Value = a[j]
cur.execute("Select * from SECVE")
secdata=list(cur.fetchall())
#writes to the second sheet
datarowlen=0
for i,a in enumerate(secdata):
datarowlen = len(a)
for j,b in enumerate(a):
secws.Cells(i+1,j+1).Value = a[j]
#saves the report
wb.SaveAs()
wb.Close()
我运行代码时遇到的错误是
Traceback (most recent call last):
File "main.py", line 369, in <module>
wb = excel.Workbooks.Open(template)
File "<COMObject <unknown>>", line 8, in Open
pywintypes.com_error: (-2147352567, 'Exception occurred.', (0, 'Microsoft Excel'
, "Microsoft Excel cannot access the file 'path to stuff------------------------
Poop Report\\Poop.xlsx'. There are several possible reasons:\n\n\u2022 The file
name or path does not exist.\n\u2022 The file is being used by another program.\
n\u2022 The workbook you are trying to save has the same name as a currently ope
n workbook.", 'xlmain11.chm', 0, -2146827284), None)
我收到一个弹出对话框,提示访问被拒绝。该文件不是只读的,我是它试图打开的工作簿的所有者。我试过了
win32.gencache.EnsureDispatch('Excel.Application')
我仍然遇到同样的错误。有什么我想念的吗?我切换到动态思维后期绑定会解决这个错误。
我在尝试修复此代码时遇到的另一个错误是 Pywins -2147418111 错误。
【问题讨论】:
-
您的
folderpath变量来自哪里?因为看起来您正在向 Excel 传递路径'path to stuff------------------------ Poop Report\\Poop.xlsx',这显然不是有效路径,这正是您收到该错误的原因。 -
我只是把它放在那里以隐藏路径,路径不是问题,因为我使用 openpyxt 没有问题,但是它无法处理数据透视表或更新它们。
标签: python excel winapi pywin32 win32com