【发布时间】:2015-02-19 06:13:15
【问题描述】:
在我的应用程序中,我在 Listview 上注册了 ContextMenu,我希望通过上下文菜单点击 Listview 项目。例如,如果我在具有这种结构的列表视图中有两行:
public class StructReceiveSms{
public int userID;
public String username;
}
我的适配器可以在列表视图中显示用户名。现在我在下面的代码中可以在列表视图上定义 conext 菜单:
public class FragmentSmsReceiveMaster extends Fragment {
private static final Boolean DEBUG = true;
public ArrayAdapter adapter;
private ArrayList<StructReceiveSms> receiveSmsArray;
.
.
.
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
.
.
.
smsView = (ListView) view.findViewById(R.id.listView);
smsView.setAdapter(adapter);
registerForContextMenu(smsView);
.
.
.
}
@Override
public void onCreateContextMenu(ContextMenu menu, View v, ContextMenuInfo menuInfo) {
AdapterView.AdapterContextMenuInfo info = (AdapterView.AdapterContextMenuInfo) menuInfo;
String[] menuItems = getResources().getStringArray(R.array.SmsMasterContextMenu);
for (int i = 0; i < menuItems.length; i++) {
menu.add(Menu.NONE, i, i, menuItems[i]);
}
}
@Override
public boolean onContextItemSelected(MenuItem item) {
AdapterView.AdapterContextMenuInfo info = (AdapterView.AdapterContextMenuInfo) item.getMenuInfo();
int menuItemIndex = item.getItemId();
String listItemName = adapter.getItem(info.position) + "";
/* GET CLICKED LISTVIEW ITEM AFTER CHOOSE CONTEXTMENU MENU ITEMS */
Toast.makeText(G.currentActivity, listItemName, Toast.LENGTH_SHORT).show();
return true;
}
}
现在单击上下文菜单项后,我可以通过menuItemIndex 获取用户单击的哪个项目,但我无法在onContextItemSelected 函数中获取Listview 的哪些项目。例如,在第一个项目上打开上下文菜单,我可以得到 userID 和 username 并显示它。怎么做,谢谢
【问题讨论】: