【发布时间】:2019-05-14 23:06:44
【问题描述】:
我正在尝试为网络爬虫创建 GUI。当他们按下搜索按钮时,我希望出现一个显示“正在搜索...”的文本
public class Main extends Application {
private CrawlerTest c;
private Scene scene1, scene2;
private String urls;
private Text urlsText, searchText;
public static void main(String[] args) {
launch(args);
}
@Override
public void start(Stage primaryStage) {
this.c = new CrawlerTest();
primaryStage.setTitle("WebCrawler");
//layout1
TextField searchInput = new TextField();
TextField keyword = new TextField();
Label searchLabel = new Label("Website URL");
searchLabel.setLabelFor(searchInput);
Label keywordLabel = new Label("Search for keyword");
keywordLabel.setLabelFor(keyword);
Button searchButton = new Button();
searchButton.setText("Search!");
this.searchText = new Text("");
this.searchText.setFont(new Font(20));
searchButton.setOnAction(e -> {
if (this.checkURL(searchInput.getText())) {
this.searchText.setText("Searching... This may take a while.");
this.urls = this.c.run(searchInput.getText(), keyword.getText());
primaryStage.setScene(scene2);
this.urlsText.setText(this.urls);
}
else {
AlertError.display("Error!", "Entered URL format is incorrect");
}
});
FlowPane container = new FlowPane();
container.getChildren().addAll(searchInput, keyword, searchButton);
VBox layout1 = new VBox(10);
layout1.setPadding(new Insets(20, 20, 20, 20));
layout1.getChildren().addAll(searchLabel, searchInput, keywordLabel, keyword, this.searchText, searchButton);
scene1 = new Scene(layout1, 300, 250);
问题是
this.searchText.setText("Searching... This may take a while.");
当它在 if 语句 if (this.checkURL(searchInput.getText())) 中时不会更改文本,但它确实在 if 语句之外工作。当我尝试调试它并且它起作用时,我知道输入了这个 if 语句。单击按钮时,有人可以帮我更改 searchText 的文本吗?谢谢!
【问题讨论】:
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CrawlerTest.run 是否立即返回?如果这是一个冗长的操作,它会阻止你的 UI 更新,因为它会阻塞 JavaFX 应用程序线程。