像这样试试。
List<Map<String,Integer>> list = List.of(
Map.of("A", 2),
Map.of("A", 3),
Map.of("B", 1),
Map.of("B", 4),
Map.of("A", 3));
Map<String, Double> avgs = list.stream()
.flatMap(m -> m.entrySet().stream())
.collect(Collectors.groupingBy(
Entry::getKey,
Collectors.averagingInt(Entry::getValue)));
System.out.println(avgs);
打印
{A=2.6666666666666665, B=2.5}
正如建议的那样,如果您不熟悉流,这里是一种迭代方法。
Map<String,Double> avgs = new HashMap<>();
Map<String,Integer> count = new HashMap<>();
for (Map<String,Integer> map : list) {
for (Entry<String,Integer> e : map.entrySet()) {
String key = e.getKey();
int value = e.getValue();
// These just either initialize or update the appropriate
// values.
avgs.compute(key, (k,v)-> v == null ? value : v + value);
count.compute(key, (k,v)->v == null ? 1 : v + 1);
}
}
// now find the averages.
for(Entry<String,Double> e : avgs.entrySet()) {
avgs.computeIfPresent(e.getKey(), (k,v)->v/count.get(e.getKey()));
}
System.out.println(avgs);