从 XML 检索数据

Question

我有一个肥皂网络服务，它返回给定的响应：

<soap:Envelope xmlns:soap="">
<soap:Body>
  <ns2:getRegisterValuesResponse xmlns:ns2="">
     <return>
        <id>11931</id>
        <value>0</value>
     </return>
     <return>
        <id>11946</id>
        <value>0</value>
     </return>
     <return>
        <id>11961</id>
        <value>0</value>
     </return>
  </ns2:getRegisterValuesResponse>
</soap:Body>
</soap:Envelope>

如何在 java 方法中检索给定的整数？

这是我的方法。我们的想法是使用给定的 id 和值每 X 分钟更新一次数据库。

public class RegisterLog implements Job {

public void execute(final JobExecutionContext ctx)
        throws JobExecutionException {
    SimulatorSOAPClientSAAJ sc=new SimulatorSOAPClientSAAJ();
    SOAPMessage msg = sc.sOAPConnect();
    ByteArrayOutputStream out = new ByteArrayOutputStream();
    try {
        msg.writeTo(out);
    } catch (SOAPException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }
    String strMsg = new String(out.toByteArray());
    System.out.println(strMsg);

Answer 1

使用 DOM XML 解析器 http://www.w3schools.com/dom/default.asp

进口

import java.io.ByteArrayInputStream;

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;

import org.w3c.dom.*;

代码

DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
ByteArrayInputStream bais = new ByteArrayInputStream(out.toByteArray());
Document doc = dBuilder.parse(bais);
doc.getDocumentElement().normalize();
NodeList nList = doc.getElementsByTagName("return");
for (int i=0;i<nList.getLength();i++) {
   Node nNode = nList.item(i);
   if (nNode.getNodeType() == Node.ELEMENT_NODE) {
      Element curElement = (Element) nNode;
      int id = Integer.parseInt(curElement.getElementsByTagName("id").item(0).getTextContent()); 
      String value = curElement.getElementsByTagName("value").item(0).getTextContent();   
   }
}