【问题标题】:Convert JSON array to Java Class Object List将 JSON 数组转换为 Java 类对象列表
【发布时间】:2016-01-27 10:10:17
【问题描述】:

我有一个来自 WFC 服务的 JSON 字符串。当我尝试将 JSON 数组转换为 List 对象时,出现以下错误:

".JsonMappingException: Can not deserialize instance of java.util.ArrayList out of START_OBJECT token at [Source: java.io.StringReader@41f27f18; line: 1, column: 1]"

Java 类(Card Class):

public class Card {
    public String ID;
    public String CompanyID;
    public String CompanyName;
    public String FiscalCode;
    public String Limit;
    public String StateID;
    public String CardState;
    public String Deleted;
    public String Sold;
    public String StartDate;
    public String InvoiceStartDate;
    public String Quantity;
    public String Value;
    public String CardTypeID;
    public String CardType;
    public String SoldChanged;
    public String DriverName;
    public String VehiclePlateNumber;
    public String VehicleID;
    public String Discount;
    public String ContractID;
    public String DiscountPerMonth;
    public String ProductID;
    public String ProductStateID;
    public String Mail;
    public String WithoutLimit;
    public String ContractSold;
    public String ContractLimit;
    public String NumberOfTransactions;
    public String DriverNameOnly;
    public String DriverSurnameOnly;
}

要反序列化的 Java 代码:

strResponse = responseHandler.handleResponse(response);
if (strResponse.contains("Credit") || strResponse.contains("Debit")) {
    ObjectMapper mapper = new ObjectMapper();
    strResponse= strResponse.replace("\"GetCardsResult\":", "");
    userCards = mapper.readValue(strResponse, mapper.getTypeFactory().constructCollectionType(List.class, Card.class));
}

JSON 字符串:

{     "GetCardsResult":"[{\"ID\":3,\"CompanyID\":1155,\"CompanyName\":\"test\",\"FiscalCode\":null,\"Code\":\"1423127205\",\"Limit\":0.000,\"StateID\":1,\"CardState\":\"Activ\",\"Deleted\":false,\"Sold\":0.000,\"StartDate\":\"\/Date(1412974800000+0300)\/\",\"InvoiceStartDate\":\"\/Date(-62135596800000+0200)\/\",\"Quantity\":null,\"Value\":0.0,\"CardTypeID\":1,\"CardType\":\"Credit\",\"SoldChanged\":false,\"DriverName\":\"\",\"VehiclePlateNumber\":\"B 222 ART\",\"VehicleID\":null,\"Discount\":null,\"ContractID\":15,\"DiscountPerMonth\":null,\"ProductID\":null,\"ProductStateID\":null,\"Mail\":\"\",\"WithoutLimit\":true,\"ContractSold\":null,\"ContractLimit\":null,\"NumberOfTransactions\":null,\"DriverNameOnly\":null,\"DriverSurnameOnly\":null},{\"ID\":2881,\"CompanyID\":1155,\"CompanyName\":\"test\",\"FiscalCode\":null,\"Code\":\"test0000\",\"Limit\":125.000,\"StateID\":1,\"CardState\":\"Activ\",\"Deleted\":false,\"Sold\":132.330,\"StartDate\":\"\/Date(1436130000000+0300)\/\",\"InvoiceStartDate\":\"\/Date(-62135596800000+0200)\/\",\"Quantity\":null,\"Value\":0.0,\"CardTypeID\":1,\"CardType\":\"Credit\",\"SoldChanged\":false,\"DriverName\":\"aaa aaa\",\"VehiclePlateNumber\":\"aaa\",\"VehicleID\":null,\"Discount\":null,\"ContractID\":15,\"DiscountPerMonth\":null,\"ProductID\":null,\"ProductStateID\":null,\"Mail\":\"\",\"WithoutLimit\":true,\"ContractSold\":null,\"ContractLimit\":null,\"NumberOfTransactions\":null,\"DriverNameOnly\":null,\"DriverSurnameOnly\":null}]" }

提前致谢!

【问题讨论】:

  • 如何将 json 字符串转换为 Object 类?
  • 我认为 ObjectMapper 会这样做 :) 这就是为什么我所有的类变量都是字符串
  • 我猜他正在使用 com.fasterxml.jackson.databind.ObjectMapper。
  • org.json.JSONObject;
  • strResponse= strResponse.replace("\"GetCardsResult\":", ""); 会破坏你的 JSON。您只删除了键和冒号,而不是前导和尾随花括号。此外:您的代码效率非常低(必须处理字符串最多四次)并且可能会中断(例如,Web 服务返回格式化的 JSON,冒号前有一个空格)

标签: java android json


【解决方案1】:

试试这个:

    try {            
         JSONObject jsonObject = null;
         yourJSONString.replace("\\", "");
         jsonObject = new JSONObject(yourJSONString);
         String newJSONString = jsonObject.get("GetCardsResult").toString();
         JSONArray jsonMainArr = new JSONArray(newJSONString);
         //now just loop the json Array
         for (int i = 0; i < jsonMainArr.length(); ++i) {                     
         JSONObject rec = jsonMainArr.getJSONObject(i);                     
         card.set_id(rec.get("ID").toString());                     
         //....      
       }                                                       
       } catch (JSONException e) {
         e.printStackTrace();
       } 

【讨论】:

【解决方案2】:

尝试使用 GSON,它非常高效且易于实现,如下示例将是您的 POJO 类。

public class Post {

    @SerializedName("id")
    public long ID;
    public String title;
    public String author;
    public String url;
    @SerializedName("date")
    public Date dateCreated;
    public String body;

    public List tags;

    public Post() {

    }
}

//Tag.java
public class Tag {

    public String name;
    public String url;

    public Tag() {

    }
}

这将是您将 JSON 字符串解析为对象类的方式,

Reader reader = new InputStreamReader(content);
GsonBuilder gsonBuilder = new GsonBuilder();
gsonBuilder.setDateFormat("M/d/yy hh:mm a");
Gson gson = gsonBuilder.create();
List<Post> posts = new ArrayList<Post>();
posts = Arrays.asList(gson.fromJson(reader, Post[].class));
content.close();

【讨论】:

    【解决方案3】:
    1. 在编译正则表达式之前或之后向映射器传递什么 - 字符串?

    2. 您是否尝试过像 Gson 这样的外部库?您需要的只是new Gson().fromJson(strResponse, new TypeToken&lt;List&lt;Card&gt;&gt;() {}.getType(););

    【讨论】:

    • userCards= gs.fromJson(strResponse, new TypeToken>() {}.getType()); java.lang.IllegalStateException:应为 BEGIN_ARRAY,但在第 1 行第 2 列是 BEGIN_OBJECT
    • 那么 new Gson().fromJson(strResponse, Card.class);
    • 你认为有一个对象,而不是一个数组?
    • 无法将数组转换为卡片对象。当然,JSON 响应中有一个数组。有超过 1 个卡信息,所以,我需要数组,前提是我以某种方式逐个对象转换
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