PHP 多维数组访问 - 五维

Question

关于我为什么这样做的参考，我正在尝试使用 SOAP / AXL WSDL API。我正在做的那部分工作就是以我可以访问的方式构建数组构造。

此处提供 API 要求以供参考。我面临的挑战是为每个上部数组元素构建成员数组。 https://developer.cisco.com/media/axl-schema-11-0/Files/AXLSoap_AddCssReq.html#Link68

数组构造：

    `$cssnames = array(
                array("name"=>"US-420-blah Gateway",
                        "description"=>"US-420 Gateway CSS",
                        "members"=>array(
                                        array(
                                            "member"=>array(
                                                "Index"=>"1",
                                                "Routeparition"=>"fancyParition"),
                                        array("member"=>array(
                                                "Index"=>"2",
                                                "Routeparition"=>"otherpartition")
                                            )))),
                array("name"=>"US-420-blah Internal Local DN CallFwd",
                        "description"=>"US-420 CSS for Call Forward",
                        "members"=>array(
                                        array(
                                            "member"=>array(
                                                "Index"=>"1",
                                                "Routeparition"=>"fancyParition"),
                                        array("member"=>array(
                                                "Index"=>"2",
                                                "Routeparition"=>"otherpartition")
                                            )))),
                array("name"=>"US-420-blah Internal Local LD DN CallFwd",
                        "description"=>"US-420 for Call Forward LD Allowed",
                        "members"=>array(
                                        array(
                                            "member"=>array(
                                                "Index"=>"1",
                                                "Routeparition"=>"fancyParition"),
                                        array("member"=>array(
                                                "Index"=>"2",
                                                "Routeparition"=>"otherpartition")
                                            )))),
                array("name"=>"US-420-blah Phones Device",
                        "description"=>"US-420 Device CSS",
                        "members"=>array(
                                        array(
                                            "member"=>array(
                                                "Index"=>"1",
                                                "Routeparition"=>"fancyParition"),
                                        array("member"=>array(
                                                "Index"=>"2",
                                                "Routeparition"=>"otherpartition")
                                            )))),
                array("name"=>"US-420-blah Phones Device Internal Only",
                        "description"=>"US-420 Device CSS Internal",
                        "members"=>array(
                                        array(
                                            "member"=>array(
                                                "Index"=>"1",
                                                "Routeparition"=>"fancyParition"),
                                        array("member"=>array(
                                                "Index"=>"2",
                                                "Routeparition"=>"otherpartition")
                                            )))));                          
foreach($cssnames['members'] as $items){
        echo($items['0']['member'] . "</br>");
        }`

这里的目标是能够使用 foreach 来遍历每个数组成员并能够为一个 CSS 返回一个完整的值。所以一个完整的 CSS 如下：

array("name"=>"US-420-blah Gateway", "description"=>"US-420 Gateway CSS", "members"=>array( array( "member"=>array( "Index"=>"1", "Routeparition"=>"fancyParition"), array("member"=>array( "Index"=>"2", "Routeparition"=>"otherpartition") )))),

根据思科文档，CSS 包含以下元素：

• 姓名
• 说明
• 成员

成员本身包含以下多个键值对：

• 索引
• RouteParitionName

问题

1. 我的数组结构是否正确？我想我这样做是因为每个“成员”都需要是一个数组，因为键值对发生冲突。
2. 如果可能的话，我如何使用 foreach 循环访问每个 KVP？
3. 我是不是把这一切都搞错了？

测试 所以我开始取得一些进展，但我有点迷茫。由于数组有 5 个级别，现在我必须循环 5 次才有意义。我不知道该怎么做就是只提取我感兴趣的 KVP。

半工作回报。

$cssnames = array("css_list"=>
                array("name"=>"US-420-blah Gateway",
                        "description"=>"US-420 Gateway CSS",
                        "members"=>array(
                                        array("member"=>array(
                                                "Index"=>"1",
                                                "Routeparition"=>"fancyParition"),
                                        array("member"=>array(
                                                "Index"=>"2",
                                                "Routeparition"=>"otherpartition")
                                            )))));

foreach($cssnames as $items=>$css){
    foreach ($css as $name=>$test){ 
        echo($test . "</br>");
        foreach($test as $memberlist=>$member){
            foreach($member as $memberitems=>$memberdetails){
                foreach($memberdetails as $details=>$config){
                    echo($config . "</br>");    
                }
            }
        }
    }
}

更新

所以还有一些进展。我意识到我有一个数组只包含一个数组项。太没有意义了。一旦我删除它似乎更有意义。我现在正在进行更多测试。更新代码：

$cssnames = array("css_list"=>
                array("name"=>"US-420-blah Gateway",
                        "description"=>"US-420 Gateway CSS",
                        "members"=>array(
                                        array(
                                                "Index"=>"1",
                                                "Routeparition"=>"fancyParition"),
                                        array(
                                                "Index"=>"2",
                                                "Routeparition"=>"otherpartition")
                                            )));

foreach($cssnames as $level1){
    echo($level1['name'] . "</br>");
    echo($level1['description'] . "</br>");

        foreach ($level1['members'] as $level2){
            echo($level2['Index'] . "</br>");
            echo($level2['Routeparition'] . "</br>");
    }
}

Answer 1

最终修复是在嵌套的 foreach 循环中以正确的顺序获取项目。

    foreach($csslist as $level1) {
        $cssname = $level1['name'];
        $cssdescription = $level1['description'];

        foreach($level1['members'] as $level2){ 
            $members[] = array(
                                "index"=>$level2['index'],
                                "routePartitionName"=>$level2['routePartitionName']);
        }
        $programTags[] = array(
                            "name"=>"$cssname",
                            "description"=>"$cssdescription",
                            "members"=>$members);
        //Empty the Members array for the next loop iteration
        $members = array();
    }