找不到元素 [bean] 的 BeanDefinitionParser

Question

我正在关注 this 教程以使用 Apache Tiles 3 我的项目 servlet-context.xml 是：

<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/mvc 
http://www.springframework.org/schema/mvc/spring-mvc.xsd        
http://www.springframework.org/schema/beans  
http://www.springframework.org/schema/beans/spring-beans.xsd        
http://www.springframework.org/schema/context 
http://www.springframework.org/schema/context/spring-context.xsd">

<!-- DispatcherServlet Context: defines this servlet's request-processing 
    infrastructure -->

<!-- Enables the Spring MVC @Controller programming model -->
<annotation-driven />

<!-- Handles HTTP GET requests for /resources/** by efficiently serving 
    up static resources in the ${webappRoot}/resources directory -->
<resources mapping="/resources/**" location="/resources/" />

<!-- Resolves views selected for rendering by @Controllers to .jsp resources 
    in the /WEB-INF/views directory -->
<beans:bean
    class="org.springframework.web.servlet.view.InternalResourceViewResolver">
    <beans:property name="prefix" value="/WEB-INF/views/" />
    <beans:property name="suffix" value=".jsp" />
</beans:bean>

<context:component-scan base-package="ali.arshad.soomro" />

<bean id="tilesConfigurer" class="org.springframework.web.servlet.view.tiles3.TilesConfigurer"> 
    <property name="definitions"> 
    <list> 
    <value>/WEB-INF/defs/general.xml</value>        
    </list> 
    </property> 
</bean> 
    <bean id="viewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver"> 
    <property name="viewClass" value="org.springframework.web.servlet.view.tiles3.TilesView" 
    /> </bean>
</beans:beans>

这里我遇到了错误

在这一行找到多个注释： - 配置问题：找不到元素 [bean] 的 BeanDefinitionParser 违规资源：文件 [G:/Spring/java-blog/src/main/webapp/ WEB-INF/spring/appServlet/servlet-context.xml] - 找不到元素 [bean] 的 BeanDefinitionParser - cvc-complex-type.2.4.c：匹配的通配符是严格的，但找不到元素'bean'的声明。

class="org.springframework.web.servlet.view.tiles3.TilesConfigurer" 行
和错误

cvc-complex-type.2.4.c：匹配的通配符是严格的，但找不到元素'bean'的声明。

class="org.springframework.web.servlet.view.UrlBasedViewResolver" 行。

pom.xml 依赖是

<dependency> 
    <groupId>org.apache.tiles</groupId> 
    <artifactId>tiles-api</artifactId> 
        <version>3.0.3</version> 
    </dependency> 
    <dependency> 
    <groupId>org.apache.tiles</groupId> 
        <artifactId>tiles-core</artifactId> 
        <version>3.0.3</version> 
    </dependency> 
    <dependency> 
    <groupId>org.apache.tiles</groupId> 
    <artifactId>tiles-jsp</artifactId> 
        <version>3.0.3</version> 
    </dependency> 
    <dependency> 
    <groupId>org.apache.tiles</groupId> 
        <artifactId>tiles-servlet</artifactId> 
        <version>3.0.3</version> 
    </dependency> 
        <dependency> 
        <groupId>org.apache.tiles</groupId> 
        <artifactId>tiles-template</artifactId> 
        <version>3.0.3</version> 
    </dependency>

更新 在下面的答案中提出建议后，我将 servlet-contex.xml 更改为

<beans:bean class="org.springframework.web.servlet.view.tiles3.TilesViewResolver">
<beans:property name="viewClass" value="org.springframework.web.servlet.view.tiles3.TilesView"></beans:property>
<beans:property name="order" value="0"></beans:property>
</beans:bean>
<beans:bean class="org.springframework.web.servlet.view.tiles3.TilesConfigurer" id="tilesConfigurer">
 <beans:property name="definitions" value="/WEB-INF/spring/tiles.xml"> </beans:property>
</beans:bean>

现在我收到此错误

属性：类 bean 类的完全限定名称，除非它仅用作子类的父定义 bean 定义。

数据类型：字符串

在线class="org.springframework.web.servlet.view.tiles3.TilesViewResolver" 并在class="org.springframework.web.servlet.view.tiles3.TilesConfigurer"
请问有人可以建议我解决这些错误吗？

Answer 1

问题在于命名空间。你应该有所有以 beans 开头的标签