生成后返回位串数组，而不仅仅是打印

Question

这是来自 geeksforgeeks 的代码，它生成并打印 n 位的位串，但我想知道，不是打印数组，而是如何存储或返回数组的值，以便我可以在 main 方法中使用这些值.

import java.util.*; 

class GFG 
{ 

// Function to print the output 
static void printTheArray(int arr[], int n) 
{ 
    for (int i = 0; i < n; i++) 
    { 
        System.out.print(arr[i]+" "); 
    } 
    System.out.println(); 
} 

// Function to generate all binary strings 
static void generateAllBinaryStrings(int n, 
                            int arr[], int i) 
{ 
    if (i == n) 
    { 
        printTheArray(arr, n); 
        return; 
    } 

    // First assign "0" at ith position 
    // and try for all other permutations 
    // for remaining positions 
    arr[i] = 0; 
    generateAllBinaryStrings(n, arr, i + 1); 

    // And then assign "1" at ith position 
    // and try for all other permutations 
    // for remaining positions 
    arr[i] = 1; 
    generateAllBinaryStrings(n, arr, i + 1); 
} 

// Driver Code 
public static void main(String args[]) 
{ 
    int n = 4; 

    int[] arr = new int[n]; 

    // Print all binary strings 
    generateAllBinaryStrings(n, arr, 0); 
} 
} 

// This code is contributed by 
// Surendra_Gangwar 

Answer 1

1. 更改返回类型
2. 添加退货声明

像这样：

// Function to generate all binary strings 
static int[] generateAllBinaryStrings(int n, 
//     ^^^^^ change return type
                            int arr[], int i) 
{ 
    if (i == n) 
    { 
        printTheArray(arr, n); 
        return; 
    } 

    // First assign "0" at ith position 
    // and try for all other permutations 
    // for remaining positions 
    arr[i] = 0; 
    generateAllBinaryStrings(n, arr, i + 1); 

    // And then assign "1" at ith position 
    // and try for all other permutations 
    // for remaining positions 
    arr[i] = 1; 
    generateAllBinaryStrings(n, arr, i + 1); 

    return arr;
//  ^^^^^^^^^^^ add return statement
}