【发布时间】:2015-08-20 21:59:26
【问题描述】:
我有以下课程
namespace Extractor.Mapping
{
public class Application
{
public virtual Guid Id { get; set; }
public virtual string intId { get; set; }
virtual SQuery sQuery { get; set; }
}
}
namespace Extractor.Mapping
{
public class SQuery
{
public virtual int Id { get;set; }
public virtual Guid Application { get;set; }
public virtual string Type { get;set; }
}
}
SQuery 和Application 的关系是SQuery 中名为“Application”的FK
这些是 de hbm 文件
应用程序.hbm.xml
<hibernate-mapping xmlns="urn:nhibernate-mapping-2.2"
assembly="Extractor"
namespace="Extractor.Mapping">
<class name="Application" >
<id name="Id" column="Id">
<generator class="assigned"/>
</id>
<property name = "intId" column = "IntId" type = "string"/>
<one-to-one name="sQuery" property-ref ="Application" class="SicQuery"/>
</class>
</hibernate-mapping>
<?xml version="1.0" encoding="utf-8" ?>
SQuery.hbm.xml
<hibernate-mapping xmlns="urn:nhibernate-mapping-2.2"
assembly="BuroExtractorD"
namespace="BuroExtractorD.Mapping">
<class name="SQuery" >
<id name="Id" column="Id">
<generator class="increment"/>
</id>
<property name="Application" column="Application" type ="Guid"/>
<property name="Type" column="Type" type="string"/>
</class>
</hibernate-mapping>
所以,事情是这样的,当我尝试访问一些 SQuery 对象的列表时,我得到以下异常:
NHibernate.PropertyAccessException: Invalid Cast (check your mapping for property type mismatches); setter of Extractor.Mapping.SQuery ---> System.InvalidCastException
我尝试像这样到达那里:
ICriteria crit = session.CreateCriteria(typeof(SQuery));
IList<SQuery> list = crit.List<SQuery>();
提前致谢
【问题讨论】:
标签: c# nhibernate nhibernate-mapping one-to-one