【发布时间】:2016-03-29 19:53:29
【问题描述】:
我有两个具有多对多关系的表。 products(id, description, price,image)----> products_category(idProducts, category_id)----> category(id, category_name).
这是我的实体:
1.产品
@Entity
@Table(name = "products")
public class Products implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(name = "idProducts")
private long id;
@Column(name = "description")
private String description;
@Column(name = "price")
private String price;
@Column(name = "image")
private byte [] image;
public Products() {
}
public Products(String description, String price, byte[] image) {}
@ManyToMany
@JoinTable(
name = "category_products",
joinColumns ={@JoinColumn (name = "Products_idProducts", referencedColumnName = "idProducts")},
inverseJoinColumns = {@JoinColumn(name = "category_id", referencedColumnName = "id")}
)
List<Category> categories = new ArrayList<>();
@ManyToMany
@JoinTable(
name = "users_product",
joinColumns ={@JoinColumn (name = "Products_idProducts", referencedColumnName = "idProducts")},
inverseJoinColumns = {@JoinColumn(name = "users_id", referencedColumnName = "id")}
)
List<Users> usersList = new ArrayList<>();
2.类别
@Entity
@Table(name = "category")
public class Category {
@Id
@Column(name = "id")
private long id;
public Category() {
}
public Category(String category_name) {
this.category_name = category_name;
}
@Column (name = "category_name")
private String category_name;
@ManyToMany(mappedBy = "categories")
private List<Products> products = new ArrayList<>();
我正在尝试为控制器编写查询,它通过先前选择的带有 id 的类别对象返回所有产品?我尝试了很多查询,但都抛出异常。
public List<Products> list (Category category) {
//category - object with needed id
Query query;
query = entityManager.createQuery("SELECT c FROM Category c left join c.categories WHERE c.category = :category", Products.class);
query.setParameter("category", category);
return (List<Products>) query.getResultList();
}
java.lang.IllegalArgumentException: org.hibernate.QueryException: could not resolve property: categories of: classes.Category [SELECT c FROM classes.Category c join c.categories WHERE c.category = :category]
org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1750)
org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1677)
org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1683)
【问题讨论】:
标签: java database hibernate hql