【发布时间】:2015-01-02 11:05:09
【问题描述】:
我有一个代码在java 中读取受保护的 excel,但该代码给了我错误。
我的java代码。
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.security.GeneralSecurityException;
import java.util.Iterator;
import org.apache.poi.hssf.usermodel.HSSFCell;
import org.apache.poi.hssf.usermodel.HSSFRow;
import org.apache.poi.hssf.usermodel.HSSFSheet;
import org.apache.poi.hssf.usermodel.HSSFWorkbook;
import org.apache.poi.poifs.crypt.Decryptor;
import org.apache.poi.poifs.crypt.EncryptionInfo;
import org.apache.poi.poifs.filesystem.POIFSFileSystem;
public class REadProtectedExcel {
public static void main(String[] args) {
String fname = "D:/Vijay/BRS_docs/10168/20.11.2014/20.11.2014/JCR_30.12.14_I Pay.xls";
try {
POIFSFileSystem fs = new POIFSFileSystem(new FileInputStream(fname));
EncryptionInfo info = new EncryptionInfo(fs);
Decryptor d = Decryptor.getInstance(info);
if (d.verifyPassword("vijay")) {
System.out.println("Password correct");
FileInputStream fis = new FileInputStream(fname);
HSSFWorkbook workbook = new HSSFWorkbook(fis);
HSSFSheet sheet = workbook.getSheetAt(0);
Iterator rowIter = sheet.rowIterator();
while (rowIter.hasNext()) {
HSSFRow myRow = (HSSFRow) rowIter.next();
Iterator cellIter = myRow.cellIterator();
while (cellIter.hasNext()) {
String cellvalue = "";
HSSFCell myCell = (HSSFCell) cellIter.next();
if (myCell.getCellType() == HSSFCell.CELL_TYPE_STRING) {
cellvalue = myCell.getStringCellValue();
} else if (myCell.getCellType() == HSSFCell.CELL_TYPE_NUMERIC) {
cellvalue = "" + myCell.getNumericCellValue();
} else if (myCell.getCellType() == HSSFCell.CELL_TYPE_BOOLEAN) {
cellvalue = "" + myCell.getBooleanCellValue();
} else if (myCell.getCellType() == HSSFCell.CELL_TYPE_FORMULA) {
cellvalue = "" + myCell.getCellFormula();
} else if (myCell.getCellType() == HSSFCell.CELL_TYPE_BLANK) {
cellvalue = "";
}
System.out.println("cellvalue--" + cellvalue);
}
}
} else {
System.out.println("Password wrong");
}
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} catch (GeneralSecurityException e) {
e.printStackTrace();
}
}
}
这段代码给了我以下错误。
java.io.FileNotFoundException: no such entry: "EncryptionInfo"
at org.apache.poi.poifs.filesystem.DirectoryNode.getEntry(DirectoryNode.java:375)
at org.apache.poi.poifs.filesystem.DirectoryNode.createDocumentInputStream(DirectoryNode.java:177)
at org.apache.poi.poifs.crypt.EncryptionInfo.<init>(EncryptionInfo.java:45)
at org.apache.poi.poifs.crypt.EncryptionInfo.<init>(EncryptionInfo.java:39)
at com.test.arrayList.REadProtectedExcel.main(REadProtectedExcel.java:22)
- 我正在使用 poi3.9 jar,xmlbeans-2.3.0jar,poi-ooml-3.6
- 我没有收到此问题。在此先感谢。
- 或者请分享另一种读取 .xls 文件的方法。
【问题讨论】:
-
你试过 xlsx 吗? xls 是硬性要求吗?
-
Password Protected Excel File 的可能重复项并寻找 poi 的第二个答案
-
第二个答案不起作用。
标签: java apache-poi xls