perl 5.8.8 和 5.10.1 之间的差异行为

Question

我有这个脚本：

#!/usr/bin/perl
$LOGFILE = "Soccer.txt";
open(LOGFILE) or die("Could not open log file.");
foreach $line (<LOGFILE>) {
    chomp $line;
    ($hour, $match, $idh, $back1, $lay1, $idd, $backx, $layx, $ida, $back2, $lay2) = split(/\s*,\s*/,$line);
    $match =~ s/^(\d{2}):(\d{2}) //g; #/ # fix highlighting
    ($hteam,$ateam) = split(/\s*§\s*/,$match,2);
    $hteam = get_name($hteam);
    $ateam = get_name($ateam);
    $match = "$hteam - $ateam";

    $foo=qq($hour "$match" $idh $back1 $lay1 $idd $backx $layx $ida $back2 $lay2 \n) ;
    print $foo;
}
sub get_name {
# Return the full name for the team, if it exists, otherwise return the original
    my %alias = (
        "Aalen" => "Vfr Aalen",
        "Accrington" => "Accrington Stanley",
        "Accrington St" => "Accrington Stanley",
        "Adelaide Utd" => "Adelaide United Fc"
    );
    return $alias{$_[0]} // $_[0];
}

这个脚本在我的系统中完美运行：

perl, v5.10.1 (*) built for i686-linux-gnu-thread-multi

现在我想在不同的系统中运行它：

perl, v5.8.8 built for x86_64-linux-thread-multi

当我尝试运行它时，我得到了这个错误：

Search pattern not terminated at ./scriptbd.robot.pl line 458.

为什么我会收到错误消息？

Answer 1

return $alias{$_[0]} // $_[0];

// operator was added in 5.10。要使其适用于早期的 Perls，请重写它：

return (defined $alias{$_[0]}) ? $alias{$_[0]} : $_[0];