【发布时间】:2012-03-03 21:09:19
【问题描述】:
我有以下 Ada 小程序:
procedure Leaky_Main is
task Beer;
task body Beer is
begin
null;
end Beer;
begin
null;
end Leaky_Main;
所有都相当基本,但是当我这样编译时:
gnatmake -g -gnatwI leaky_main.adb
并像这样通过 Valgrind 运行它:
valgrind --tool=memcheck -v --leak-check=full --read-var-info=yes --leak-check=full --show-reachable=yes ./leaky_main
我收到以下错误摘要:
==2882== 2,104 bytes in 1 blocks are still reachable in loss record 1 of 1
==2882== at 0x4028876: malloc (vg_replace_malloc.c:236)
==2882== by 0x42AD3B8: __gnat_malloc (in /usr/lib/i386-linux-gnu/libgnat-4.4.so.1)
==2882== by 0x40615FF: system__task_primitives__operations__new_atcb (in /usr/lib/i386-linux-gnu/libgnarl-4.4.so.1)
==2882== by 0x406433C: system__tasking__initialize (in /usr/lib/i386-linux-gnu/libgnarl-4.4.so.1)
==2882== by 0x4063C86: system__tasking__initialization__init_rts (in /usr/lib/i386-linux-gnu/libgnarl-4.4.so.1)
==2882== by 0x4063DA6: system__tasking__initialization___elabb (in /usr/lib/i386-linux-gnu/libgnarl-4.4.so.1)
==2882== by 0x8049ADA: adainit (b~leaky_main.adb:142)
==2882== by 0x8049B7C: main (b~leaky_main.adb:189)
==2882==
==2882== LEAK SUMMARY:
==2882== definitely lost: 0 bytes in 0 blocks
==2882== indirectly lost: 0 bytes in 0 blocks
==2882== possibly lost: 0 bytes in 0 blocks
==2882== still reachable: 2,104 bytes in 1 blocks
==2882== suppressed: 0 bytes in 0 blocks
==2882==
==2882== ERROR SUMMARY: 0 errors from 0 contexts (suppressed: 21 from 6)
--2882--
--2882-- used_suppression: 21 U1004-ARM-_dl_relocate_object
==2882==
==2882== ERROR SUMMARY: 0 errors from 0 contexts (suppressed: 21 from 6)
有谁知道为什么这被报告为错误? 我相当确定没有实际泄漏,但我想知道它为什么/如何发生。
谢谢,
【问题讨论】:
-
哪里出错了? 0 个错误,0 个字节丢失...
-
@oenone :“仍然可以访问:1 个块中的 2,104 个字节”
-
问题出在哪里?内存仍然可以访问。这没有错误,也没有这样报告。
-
当内存在程序终止后可以访问时,这是一个泄漏,这是一个问题。正如西蒙指出的那样,这可能是由于一个已知的错误。
-
我认为这不是问题。这可能并不理想,但操作系统无论如何都会释放进程使用的所有内存。
标签: memory-leaks valgrind ada