如何从内存中读取对象名称？

Question

我写了一个简单的类代码，如下所示。

class Fridge:

def __init__(self):
    self.isOpened = False
    self.foods = []

def open(self):
    self.isOpened = True

def put(self, thing):
    if self.isOpened:
        self.foods.append(thing)

def close(self):
    self.isOpened = False

class Food:
    pass

然后导入模块...

import class_practice as fridge

f = fridge.Fridge()
apple = fridge.Food()
elephant = fridge.Food()

f.open()
f.put(apple)
f.put(elephant)

print(f.foods)

打印输出是

[<class_practice.Food object at 0x7fe761fce5f8>, <class_practice.Food object at 0x7fe761fce710>]

在这种情况下，如果我想打印出f.foods作为[apple, elephant]的对象名，

我该怎么办？

##Revised##

我想从中提取数据

[<class_practice.Food object at 0x7fe761fce5f8>, <class_practice.Food object at 0x7fe761fce710>] 

如 ['apple', 'elephant'] 的形式。

就像，

a = 'hello'
b = id(a)
print(ctypes.cast(b, ctypes.py_object).value)

然后，结果是'hello'

Answer 1

将值存储在实例属性中，并从__repr__ dunder 方法返回：

class Food:
    def __init__(self, value):
        self.value = value
     
    def __repr__(self):
        return self.value

在构造Food时需要传递值：

apple = fridge.Food("apple")
elephant = fridge.Food("elephant")

Answer 2

或尝试以下方法：

class Fridge:

    def __init__(self):
        self.isOpened = False
        self.foods = []

    def open(self):
        self.isOpened = True

    def put(self, thing):
        if self.isOpened:
            self.foods.append(thing)

    def close(self):
        self.isOpened = False

class Food:
    def __init__(self, value):
        self.value = value
     
    def __repr__(self):
        return self.value

import class_practice as fridge
f = fridge.Fridge()
f.open()
f.put(fridge.Food('apple'))
f.put(fridge.Food('elephant'))
print(f.foods)

输出：

[apple, elephant]