SQL中如何计算多个字段中的单个字符答案

【问题标题】：How to count up a single character in multiple fields in SQLSQL中如何计算多个字段中的单个字符
【发布时间】：2016-06-23 15:07:33
【问题描述】：

您好，我有一个表“TableCustomers”，在这个表中有许多字段，标题为“Name1”“Name2”“Name3”......“Name40”其中一些字段只有字母“x”我想知道所有 40 个字段中有多少个“x”

【问题讨论】：

到目前为止你尝试过什么？请包括Minimal, Complete, and Verifiable example。另请阅读How do I ask a Good Question。确保您的问题是具体的，而不是过于宽泛。
可能重复？ stackoverflow.com/questions/591853/…
How to count the number of times a character appears in a SQL column?的可能重复
这些问题与计算单列中的出现次数有关，但是我认为 op 想要计算单行中出现的列数？

标签： sql

【解决方案1】：

一种可能的解决方案是这样的；

SELECT 
CASE WHEN [Name] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name1] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name2] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name3] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name4] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name5] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name6] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name7] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name8] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name9] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name10] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name11] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name12] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name13] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name14] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name15] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name16] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name17] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name18] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name19] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name20] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name21] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name22] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name23] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name24] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name25] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name26] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name27] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name28] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name29] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name30] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name31] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name32] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name33] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name34] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name35] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name36] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name37] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name38] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name39] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name40] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name41] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name42] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name43] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name44] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name45] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name46] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name47] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name48] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name49] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name50] = 'x' THEN 1 ELSE 0 END
FROM [TableCustomers]

我使用名为 Nimble Text (http://nimbletext.com/) 的应用程序生成了此语句，但如果表的列发生更改，您可以使用动态 SQL 和 sys.columns 视图在 SQL 服务器中生成此语句。如果您想要这样的示例，请告诉我...

【讨论】：

【解决方案2】：

你可以试试这样的：

    select len(name00 + name01 + .. + name40) - len(replace(name00 + name01 + .. + name40, 'x', '')) 
from yourTable;

【讨论】：