ASCII 错误消息，找不到符号

Question

私人无效 btnTranslateActionPerformed(java.awt.event.ActionEvent evt) {
字符串 strSecretMessage;

    strSecretMessage = this.txtSecretMessage.getText();

    for (int i=0; i < (strSecretMessage.length()-1); i++){
        lblACSII.setText(i+" "+ strSecretMessage.charCodeAt(i));
    }
}   

charCodeAt 出现错误，提示找不到符号。

Answer 1

lblACSII.setText(i+" "+ (int)strSecretMessage.charAt(i));

charAt() 获取 char 并将其转换为 int 将提供 ascii 值

String temp = "";
for (int i=0; i < (strSecretMessage.length()-1); i++){
     temp += i+" "+ strSecretMessage.charCodeAt(i) + " ";
 }
lblACSII.setText(temp);