【发布时间】:2014-08-08 23:21:30
【问题描述】:
所以我尝试用 Java 制作一个 Hanger 程序,当我尝试使用 get 方法输出一个变量时,它返回 null。我首先设置了一个 Scanner 对象,然后我将一个 String 设置为用户输入的值,然后我使用 set 方法将 String 设置为一个新变量,最后,我使用 get 方法调用该新变量。它返回null,我不知道为什么。
import java.util.Scanner;
public class Hanger
{
public String word;
public Hanger(){}
public void setWord(String new_word)
{
new_word = word;
}
public String getWord()
{
return word;
}
public static void main(String[] args)
{
Scanner input_names = new Scanner(System.in);
Scanner input_word = new Scanner(System.in);
Hanger word1 = new Hanger();
System.out.println("Please enter Player 1's name.");
String name1 = input_names.nextLine();
System.out.println("Please enter Player 2's name.");
String name2 = input_names.nextLine();
System.out.println("Are your names " + name1 + " and " + name2 + "?");
String names_correct = input_names.nextLine();
switch (names_correct)
{
case "no":
{
System.out.println("Please enter Player 1's name.");
name1 = input_names.nextLine();
System.out.println("Please enter Player 2's name.");
name2 = input_names.nextLine();
System.out.println("Are your names " + name1 + " and " + name2 + "?");
names_correct = input_names.nextLine();
}
case "No":
{
System.out.println("Please enter Player 1's name.");
name1 = input_names.nextLine();
System.out.println("Please enter Player 2's name.");
name2 = input_names.nextLine();
System.out.println("Are your names " + name1 + " and " + name2 + "?");
names_correct = input_names.nextLine();
}
default:
{
break;
}
}
System.out.println("Let's begin! " + name1 + ", please type a word that " + name2 + " will try to guess.");
String input_word1 = input_word.nextLine();
word1.setWord(input_word1);
System.out.println("Is " + word1.getWord() + " correct?");
}
}
【问题讨论】: