我会尝试使用不错的快速安全哈希函数 - ChaCha20。
ChaCha20 生成每个 64 字节的伪随机块,这些块与要加密或解密的数据进行异或运算。它需要 256 位密钥和 64 位随机数。假设您的所有 ID 都适合 64 位(毕竟,20 位数字非常接近 264-1,即 18,446,744,073,709,551,615),设置您的密钥,使用组 ID 作为随机数,并加密您记录的 Id XORing用它ChaCha20输出。
你没有提到平台,所以没有代码,但是在 C/C++/Go/Rust/...中有很多很好的实现...
更新
您可以尝试在计数器模式下使用 ChaCha20 作为分组密码。然后您的输入将是键,64 位组 id 作为随机数,64 位记录 id 作为计数器。输出将是您发送给客户的 64 位块。
好的,我使用 Monocypher 实现(ChaCha20 页面底部的链接),并将其用作上面建议的分组密码。到目前为止,它对我来说看起来不错——不同的 groupId/recordId 产生了截然不同的加扰值。代码使用 C++,使用 LLVM 8 和 MSVC++19.2 编译。我把整个项目放在 Github here.
uint64_t scramble(const uint64_t groupId,
const uint64_t recordId,
const char* text_key = nullptr)
{
uint8_t key[32] = {0x1c, 0x92, 0x40, 0xa5, 0xeb, 0x55, 0xd3, 0x8a,
0xf3, 0x33, 0x88, 0x86, 0x04, 0xf6, 0xb5, 0xf0,
0x47, 0x39, 0x17, 0xc1, 0x40, 0x2b, 0x80, 0x09,
0x9d, 0xca, 0x5c, 0xbc, 0x20, 0x70, 0x75, 0xc0}; // same key as in example 3 below
if (text_key != nullptr) {
hex2byte(text_key, key);
}
const uint8_t* nonce = reinterpret_cast<const uint8_t*>(&groupId); // nonce would be our group id
crypto_chacha_ctx ctx;
crypto_chacha20_init(&ctx, key, nonce); // initialize ChaCha20
crypto_chacha20_set_ctr(&ctx, recordId); // block counter is our record Id
uint64_t input = 0x0000000000000000; // Just get the block out. Chacha will make random block and XOR it with input text.
// XOR with zeroes preserve Chacha block.
// Or 0xFFFFFFFFFFFFFFFF to get it iverted
uint64_t output;
crypto_chacha20_encrypt(&ctx,
reinterpret_cast<uint8_t*>(&output),
reinterpret_cast<const uint8_t*>(&input),
sizeof(input));
return output;
}
int main()
{
// Test values from http://tools.ietf.org/html/draft-nir-cfrg-chacha20-poly1305-04#appendix-A.2
srand(123); //Test results will be consistent
test_ietf_chacha20("0000000000000000000000000000000000000000000000000000000000000000", "0000000000000000", "00000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000", "76b8e0ada0f13d90405d6ae55386bd28bdd219b8a08ded1aa836efcc8b770dc7da41597c5157488d7724e03fb8d84a376a43b8f41518a11cc387b669b2ee6586", 0, 1);
test_ietf_chacha20("0000000000000000000000000000000000000000000000000000000000000001", "0000000000000002", "416e79207375626d697373696f6e20746f20746865204945544620696e74656e6465642062792074686520436f6e7472696275746f7220666f72207075626c69636174696f6e20617320616c6c206f722070617274206f6620616e204945544620496e7465726e65742d4472616674206f722052464320616e6420616e792073746174656d656e74206d6164652077697468696e2074686520636f6e74657874206f6620616e204945544620616374697669747920697320636f6e7369646572656420616e20224945544620436f6e747269627574696f6e222e20537563682073746174656d656e747320696e636c756465206f72616c2073746174656d656e747320696e20494554462073657373696f6e732c2061732077656c6c206173207772697474656e20616e6420656c656374726f6e696320636f6d6d756e69636174696f6e73206d61646520617420616e792074696d65206f7220706c6163652c207768696368206172652061646472657373656420746f", "a3fbf07df3fa2fde4f376ca23e82737041605d9f4f4f57bd8cff2c1d4b7955ec2a97948bd3722915c8f3d337f7d370050e9e96d647b7c39f56e031ca5eb6250d4042e02785ececfa4b4bb5e8ead0440e20b6e8db09d881a7c6132f420e52795042bdfa7773d8a9051447b3291ce1411c680465552aa6c405b7764d5e87bea85ad00f8449ed8f72d0d662ab052691ca66424bc86d2df80ea41f43abf937d3259dc4b2d0dfb48a6c9139ddd7f76966e928e635553ba76c5c879d7b35d49eb2e62b0871cdac638939e25e8a1e0ef9d5280fa8ca328b351c3c765989cbcf3daa8b6ccc3aaf9f3979c92b3720fc88dc95ed84a1be059c6499b9fda236e7e818b04b0bc39c1e876b193bfe5569753f88128cc08aaa9b63d1a16f80ef2554d7189c411f5869ca52c5b83fa36ff216b9c1d30062bebcfd2dc5bce0911934fda79a86f6e698ced759c3ff9b6477338f3da4f9cd8514ea9982ccafb341b2384dd902f3d1ab7ac61dd29c6f21ba5b862f3730e37cfdc4fd806c22f221", 1, 2);
test_ietf_chacha20("1c9240a5eb55d38af333888604f6b5f0473917c1402b80099dca5cbc207075c0", "0000000000000002", "2754776173206272696c6c69672c20616e642074686520736c6974687920746f7665730a446964206779726520616e642067696d626c6520696e2074686520776162653a0a416c6c206d696d737920776572652074686520626f726f676f7665732c0a416e6420746865206d6f6d65207261746873206f757467726162652e", "62e6347f95ed87a45ffae7426f27a1df5fb69110044c0d73118effa95b01e5cf166d3df2d721caf9b21e5fb14c616871fd84c54f9d65b283196c7fe4f60553ebf39c6402c42234e32a356b3e764312a61a5532055716ead6962568f87d3f3f7704c6a8d1bcd1bf4d50d6154b6da731b187b58dfd728afa36757a797ac188d1", 42, 3);
std::cout << '\n';
uint64_t scrambled{0ULL};
scrambled = scramble(10, 12345);
std::cout << "0x" << std::hex << scrambled << '\n';
scrambled = scramble(100, 12345);
std::cout << "0x" << std::hex << scrambled << '\n';
scrambled = scramble(11, 12345); // group id differ by 1
std::cout << "0x" << std::hex << scrambled << '\n';
scrambled = scramble(10, 12346); // record id differ by 1
std::cout << "0x" << std::hex << scrambled << '\n';
scrambled = scramble(0, 0);
std::cout << "0x" << std::hex << scrambled << '\n';
scrambled = scramble(0, 1);
std::cout << "0x" << std::hex << scrambled << '\n';
scrambled = scramble(1, 0);
std::cout << "0x" << std::hex << scrambled << '\n';
return 0;
}
最后 7 行的输出是
0x6321d1e43d4ab340
0x7dd7e1cfab075076
0x1e8483e0081fa6ee
0xb6084d3151900667
0x7794b6c405fbf46
0x115ddf32dffd75df
0x87a199dff4e4326a
更新二
抱歉,我打错字可能误导了您(当块为 64 字节时,块的大小为 64 位,现已更正)。
是的,块大小是 64 字节(实际上是 16 个 uint32_t 的 32 位)。 ChaCha20 能够产生 264 个这样的块。因此,您可以将输入大小设为 12 个字节,输出将是块的前 12 个字节。请检查 repo 中的更新代码。我已经反转打印 12bytes 块以显示它与以前相同(字节序)。您可以将任何加扰的大小设置为最大 64。