如何将函数转换为 Python 中的 int？或者这甚至可能吗？

Question

问题： 我不能也不知道如何使用/将函数位置转换为函数 find_second 的输入/整数。

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代码

  # Define a procedure, find_second, that takes
  # two strings as its inputs: a search string
  # and a target string. It should return a
  # number that is the position of the second
  # occurrence of the target string in the
  # search string.

def position (search_string, target):
    position_target = search_string.find(target)
    return int(position_target)

def find_second (search_string, second_target):
    return search_string.find(second_target, position+1)

danton = "De l'audace, encore de l'audace, toujours de l'audace"

print find_second(danton, 'audace')`

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错误信息：

Traceback (most recent call last):
File "vm_main.py", line 33, in <module>
import main
File "/tmp/vmuser_laavqhjazh/main.py", line 19, in <module>
print find_second(danton, 'audace')
File "/tmp/vmuser_laavqhjazh/main.py", line 13, in find_second
return search_string.find(second_target, position+1)
TypeError: unsupported operand type(s) for +: 'function' and 'int'

Answer 1

位置是一个函数。另一种选择是：

def find_second(search_string, target):
    temp = search_string.find(target)
    return search_string.find(target, temp)

danton = "De l'audace, encore de l'audace, toujours de l'audace"

print find_second(danton, 'audace')`