Rand Dict 值在 python 中不起作用

Question

我有什么方法可以指定我想要的“ben Stiller”或“bill murray”的值吗？

我知道我不能做 random.choice(ben_stiller.values())：

我还更改了字典，所以关键是电影的名称，现在可以完美运行。

^

import random

last_man = {
    'Mark Walberg': '1',
    'Ben Stiller': '2',
    'Bill Murray': '3',

}

markymark = {
    'movie': 'The martian',
    'movie': 'The Departed',
    'movie': 'XYZ'
}

ben_stiller = {
    'movie': 'Meet the parents',
    'movie': 'Something about mary',
    'movie': 'dunno'
}

bill_murray = {
   'movie': 'Life Aquatic',
   'movie': 'rushmore',
   'movie': 'Groundhogs day'
}

print "There are three actors, one will be chosen randomly"
print "You have to name as many movies as they have been in"
print "If you get one wrong, you lose, you hae three chances, and must     get one correct"

random.choice(last_man.keys())

print "The actor randonly chosen is: ", random.choice(last_man.keys())

guesses_taken = 0

while guesses_taken <= 3:
    guess = raw_input(': ')
    guesses_taken = guesses_taken + 1

    if guess == random.choice(bill_murray.keys()):
        print "you won in %s guesses" % guesses_taken
        print guesses_taken
    elif guess == random.choice(ben_stiller.keys()):
        print "you won in %s guesses" % guesses_taken
        print guesses_taken
    elif guess == random.choice(markymark.keys()):
        print "you won in %s guesses" % guesses_taken
        print guesses_taken
    elif guess != random.choice(markymark.keys()):
        print "You lost"
        print guesses_taken
    else:
        print "you lose"
        exit(0)

Answer 1

完整的错误系统

File "movie.py", line 42
  if guess == random.choice(bill_murray.keys())
                                             ^
SyntaxError: invalid syntax

所以，语法无效。 if 行需要以 : 结尾

如果我们通过添加冒号来整理第 42 行，那么我们得到

File "movie.py", line 45
  elif guess == random.choice(ben_stiller.keys())
                                              ^
SyntaxError: invalid syntax

所以，语法无效。 elif 行需要以 : 结尾

elif guess == random.choice(ben_stiller.keys()):
#                                              ^---- and so on 

语法错误现在消失了。 现在我们还有另一个问题。 还有一个错别字

“你有三个机会，”

->

“你有三个机会，”

无论如何。如果它向我展示了

随机选择的演员是：比尔·默里

（好吧，两个错别字……）

我选择“rushmore”，它告诉我我错了。正如 cmets 所指出的，当我尝试向字典中的现有键（“电影”）添加值时，它会被替换。我们能不能给个电影清单？

另外，当我播放这个时，它没有使用电影：

The actor randonly chosen is:  Bill Murray
: rushmore
You lost
1
: Groundhogs day
You lost
2
: Life Aquatic
You lost
3
: movie
you won in 4 guesses
4

让我们改用电影列表。作为演员姓名的键的值。 并删除exit(0)

类似这样的：

import random

last_man = {
    'Mark Walberg': ['The martian', 'The Departed', 'XYZ'],
    'Ben Stiller': ['Meet the parents', 'Something about mary', 'dunno'],
    'Bill Murray': ['Life Aquatic', 'rushmore', 'Groundhogs day']

}


print "There are three actors, one will be chosen randomly"
print "You have to name as many movies as they have been in"
print "If you get one wrong, you lose, you have three chances, and must get one correct"

actor = random.choice(last_man.keys())
#^--- remember who

print "The actor randomly chosen is: ", actor

guesses_taken = 0

while guesses_taken <= 3:
    guess = raw_input(': ')
    guesses_taken = guesses_taken + 1

    if guess in last_man[actor]:
        print "you won in %s guesses" % guesses_taken
        print guesses_taken
        break
    else:
        print "you lose"