android的httppost方法不适用于名称值对

Question

下面的代码创建了一个表单，其结果将被发布到服务器（请求到服务器）...我尝试了使用具有相同表单字段的 html 的相同表单，但在这里它不起作用并重定向到主页网站页面.....

公共类 MainActivity 扩展 Activity {

Button submit,fpass;
EditText wbpasswd,wblogid;
TextView loginid,password;
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    wblogid = (EditText) findViewById(R.id.wblogid);
    wbpasswd = (EditText) findViewById(R.id.wbpasswd);
    submit = (Button) findViewById(R.id.submit);
    fpass = (Button) findViewById(R.id.fpass);
    loginid = (TextView) findViewById(R.id.loginid);
    password = (TextView) findViewById(R.id.password);
    fpass.setOnClickListener(new View.OnClickListener() {
        public void onClick(View v) {
            Toast.makeText(getBaseContext(), "You have clicked the fpass button",
                    Toast.LENGTH_SHORT).show();
        }
        });
    submit.setOnClickListener(new View.OnClickListener() {
        public void onClick(View v) {
             new Thread(new Runnable() {
                    public void run() {
            // Create a new HttpClient and Post Header
            HttpClient httpclient = new DefaultHttpClient();
            HttpPost httppost = new HttpPost("http://www.ebharatgas.com/ebgas/login");

            try {
                // Add your data
                List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
                nameValuePairs.add(new BasicNameValuePair("wblogid", wblogid.getEditableText().toString()));
                nameValuePairs.add(new BasicNameValuePair("wbpasswd", wbpasswd.getEditableText().toString()));
                httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

                // Execute HTTP Post Request
                HttpResponse response = httpclient.execute(httppost);
                String t = EntityUtils.toString(response.getEntity());
                Intent i = new Intent("com.example.ebharatgas.Activity2");
                i.putExtra("code", t);
                startActivity(i); 

            } catch (ClientProtocolException e) {
                // TODO Auto-generated catch block
            } catch (IOException e) {
                // TODO Auto-generated catch block
            }
                    }
              }).start();
            //Toast.makeText(getBaseContext(), "You have clicked the fpass button",
                    //Toast.LENGTH_SHORT).show();
        }
        });

}   

}

另外请告诉我如何在我的 android 活动中显示来自服务器的响应...我是 android 编程的初学者...请帮助我...提前致谢..

Answer 1

像这样试一试：

私有类 JsonResponse 扩展 AsyncTask {

    String response = "";

    protected void onPreExecute() 
    {

    }

    protected void onPostExecute(String result) 
    {   
        if(response.equalsIgnoreCase("Success"))
        {
        Intent i = new Intent("com.example.ebharatgas.Activity2");
            i.putExtra("code", t);
            startActivity(i); 
        }
    }
    protected String doInBackground(final String... args)
    {     List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
            nameValuePairs.add(new BasicNameValuePair("wblogid", wblogid.getEditableText().toString()));
            nameValuePairs.add(new BasicNameValuePair("wbpasswd", wbpasswd.getEditableText().toString()));
            httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

            // Execute HTTP Post Request
            HttpResponse response = httpclient.execute(httppost);
            String t = EntityUtils.toString(response.getEntity());

            }
                response = "Success";
        }
            catch(JSONException e)
                {
                    e.printStackTrace();
                }

            return response;
    }
} //Formatting & Code setting required