错误：'operator&&' 不匹配答案

【问题标题】：Error: no match for 'operator&&'错误：'operator&&' 不匹配
【发布时间】：2011-10-06 13:50:11
【问题描述】：

我收到以下错误

错误：'board[0][0] && board[0][1]'中的'operator&&'不匹配

我的代码如下：

    #include <iostream>
    #include <cstdlib>
    #include <ctime>

    using namespace std;

    int main()
    {
        string board[3][3];
         board[0][0] = "[ ]";
         board[0][1] = "[ ]";
         board[0][2] = "[ ]";
         board[1][0] = "[ ]";
         board[1][1] = "[ ]";
         board[1][2] = "[ ]";
         board[2][0] = "[ ]";
         board[2][1] = "[ ]";
         board[2][2] = "[ ]";
         string choice;
         int counter;
         do
         {
            for(counter=0;counter<5;counter++)
            {
                cout<<board[0][0]<<board[0][1]<<board[0][2]<<endl;
                cout<<board[1][0]<<board[1][1]<<board[1][2]<<endl;
                cout<<board[2][0]<<board[2][1]<<board[2][2]<<endl;
            cout<<"(Player 1) Tell me the coordinates of where you want your X togo: ";
                cin>>choice;
                cout<<endl;
                if(choice=="1,1")
                {
                    board[0][0] = "[X]";
                }
                else if(choice=="1,2")
                {
                    board[1][0] = "[X]";
                }
        else if(choice=="1,3")
        {
            board[2][0] = "[X]";
        }
        else if(choice=="2,1")
        {
            board[0][1] = "[X]";
        }
        else if(choice=="2,2")
        {
            board[1][1] = "[X]";
        }
        else if(choice=="2,3")
        {
            board[2][1] = "[X]";
        }
        else if(choice=="3,1")
        {
            board[0][2] = "[X]";
        }
        else if(choice=="3,2")
        {
            board[1][2] = "[X]";
        }
        else if(choice=="3,3")
        {
            board[2][2] = "[X]";
        }

        if(board[0][0] && board[0][1] && board[0][2] == "[X]" || board[1][0] && board[1][1] && board[1][2] == "[X]" || board[2][0] && board[2][1] && board[2][2] == "[X]" || board[0][0] && board[1][0] && board[2][0] == "[X]" || board[0][1] && board[1][1] && board[2][1] == "[X]" || board[0][2] && board[1][2] && board[2][2] == "[X]" || board[0][0] && board[1][1] && board[2][2] == "[X]" ||board[2][0] && board[1][1] && board[0][2] == "[X]" ||)
        {
            cout<<"Player 1 wins!"<<endl;
        }

    }
 }
 while(counter<5);
 return 0;

}

错误所在的行如下：

if(board[0][0] && board[0][1] && board[0][2] == "[X]" || board[1][0] && board[1][1] &&     board[1][2] == "[X]" || board[2][0] && board[2][1] && board[2][2] == "[X]" || board[0][0]    && board[1][0] && board[2][0] == "[X]" || board[0][1] && board[1][1] && board[2][1] == "[X]" || board[0][2] && board[1][2] && board[2][2] == "[X]" || board[0][0] && board[1][1] && board[2][2] == "[X]" ||board[2][0] && board[1][1] && board[0][2] == "[X]" ||)

【问题讨论】：

标签： c++ arrays compiler-errors syntax-error

【解决方案1】：

您需要更改以下内容：

board[0][0] && board[0][1] && board[0][2] == "[X]"

收件人：

board[0][0] == "[X]" && board[0][1] == "[X]" && board[0][2] == "[X]"

这样 && 两边的输入都是布尔值

【讨论】：

我应该让每组新的 3 个数组单元都成为自己的 if 语句，还是可以像我拥有的那样将它们全部保留为一个 if 语句？
@Jesus std::string 对const char * 有一个operator== 重载。它会起作用的。
您可能需要考虑为此使用宏或内联函数。否则看起来有点乱。

【解决方案2】：

我建议使用字符数组而不是字符串数组 - 然后，当您要求用户输入并且他输入说“1, 3”时 - 您可以简单地声明两个整数并使用它们：

int x, y;
scanf("%i,%i", &x, &y);
board[x][y] = 'X'; 
// and when printing the board, use: cout << "["<<board[x][y]<<"]"; 
// - or better yet, use printf :) 

// alternatively with cin:
int x, y;
cin >> x;
cin.ignore(1,',');
cin >> y;
board[x][y] = 'X';

这将缩短所有“确定用户选择的平方”代码:)

【讨论】：