【发布时间】:2016-05-11 07:21:50
【问题描述】:
您好,我有以下格式的集合
{
"_id" : ObjectId("572eb5df1d739cc73c21f953"),
"address" : {
"building" : "469",
"coord" : [
-73.961704,
40.662942
],
"street" : "Flatbush Avenue",
"zipcode" : "11225"
},
"borough" : "Brooklyn",
"cuisine" : "Hamburgers",
"grades" : [
{
"date" : ISODate("2014-12-30T00:00:00Z"),
"grade" : "A",
"score" : 8
},
{
"date" : ISODate("2014-07-01T00:00:00Z"),
"grade" : "B",
"score" : 23
},
{
"date" : ISODate("2013-04-30T00:00:00Z"),
"grade" : "A",
"score" : 12
},
{
"date" : ISODate("2012-05-08T00:00:00Z"),
"grade" : "A",
"score" : 12
}
],
"name" : "Wendy'S",
"restaurant_id" : "30112340"
}
我已经制作了 3 个非常简单的类来映射对象。餐厅、地址和等级。 它们具有以下格式 餐厅
public String _id;
public Address address;
public String town;
public String cuisine;
public String name;
public String r_id;
public Grade [] grades;
地址
public int building;
public String street;
public long zip;
public float [] coord;
等级
public String date;
public char grade;
public int score;
我已经编写了最简单的代码来只 toString() 一个映射对象,看看我得到了什么
DB db = new MongoClient().getDB("test");
Jongo j = new Jongo(db);
MongoCollection collection = j.getCollection("restaurants");
Restaurant r1 = collection.findOne().as(Restaurant.class);
System.out.println(r1);
这段代码输出
Restaurant: 572eb5df1d739cc73c21f953 / Wendy'S
Cuisine: Hamburgers
Restaurant ID: null
Address: 469 Flatbush Avenue 0, null
Grades: Tue Dec 30 05:00:00 PKT 2014 A / 8
Grades: Tue Jul 01 05:00:00 PKT 2014 B / 23
Grades: Tue Apr 30 05:00:00 PKT 2013 A / 12
Grades: Tue May 08 05:00:00 PKT 2012 A / 12
我似乎无法修复我得到的邮政编码和餐厅 ID 的空值。
请有人帮忙。谢谢。
【问题讨论】:
标签: java mapping mongodb-java jongo