【发布时间】:2013-11-22 08:29:12
【问题描述】:
我正在尝试将 .txt 文件上传到 ftp 服务器。但我有一些问题。我不断收到此错误:远程服务器返回错误:(553) 文件名不允许。
这总是发生在这一行:
Stream writer = ftpReq.GetRequestStream();
我无法弄清楚问题是什么。我试过用 filezilla 上传文件,效果很好。我还尝试从服务器复制文件目标 url 并将其硬编码到我的应用程序中,但我仍然遇到相同的错误。有没有其他方法可以将文件上传到 ftp 服务器??
这是我的代码:
string localFilePath = @"\\fileprint\data\Groups\Operation\fileExports\folder\";
string archiveFilePath = @"\\fileprint\data\Groups\Operation\fileExports\folder\Archive\";
string logFilePath = @"C:\Users\lmy\Desktop\Logs";
string ftpServer = "ftp://my.server.no:21/home/pll332/tmp/";
private string logFileName = "" + DateTime.Now.Year.ToString() + "-" + DateTime.Now.Month.ToString() + "-" + DateTime.Now.Day.ToString();
string userName = "pll332";
string password = "password";
public Controller()
{
}
public void UploadFile()
{
try
{
string[] files = Directory.GetFiles(localFilePath);
foreach (string file in files)
{
string fileName = Path.GetFileName(file);
FtpWebRequest ftpReq = (FtpWebRequest)FtpWebRequest.Create(new Uri(ftpServer + fileName));
ftpReq.Method = WebRequestMethods.Ftp.UploadFile;
ftpReq.UsePassive = true;
ftpReq.UseBinary = true;
ftpReq.KeepAlive = true;
ftpReq.Credentials = new NetworkCredential(userName.Normalize(), password.Normalize());
FileInfo fileInfo = new FileInfo(localFilePath + @"\" + fileName);
FileStream fileStream = fileInfo.OpenRead();
byte[] fileContent = new byte[fileInfo.Length];
fileStream.Read(fileContent, 0, Convert.ToInt32(fileInfo.Length));
Stream writer = ftpReq.GetRequestStream();
writer.Write(fileContent, 0, fileContent.Length);
fileStream.Close();
writer.Close();
FtpWebResponse response = (FtpWebResponse)ftpReq.GetResponse();
AppendLogFile(response, "Uploaded Files: ", fileName);
MoveToArchive(file, archiveFilePath + fileName);
}
}
catch (Exception exception)
{
Console.WriteLine(exception.Message);
}
}
希望你们能帮助我。谢谢!
编辑: 我试过这个:
string fileName = Path.GetFileName(file);
UriBuilder uri = new UriBuilder();
uri.Scheme = "ftp";
uri.Host = "my.server.no";
uri.Port = 21;
uri.Path = "/home/username/tmp/";
uri.UserName = "username";
uri.Password = "password";
FtpWebRequest ftpReq = (FtpWebRequest)FtpWebRequest.Create(new Uri(uri.ToString() + fileName));
ftpReq.Method = WebRequestMethods.Ftp.UploadFile;
ftpReq.UsePassive = true;
ftpReq.UseBinary = true;
ftpReq.KeepAlive = true;
ftpReq.Credentials = new NetworkCredential(userName.Normalize(), password.Normalize());
这给了我同样的错误......
【问题讨论】:
-
您可以尝试使用第三方组件,例如enterprisedt.com/products/edtftpnet
-
你尝试了什么?当您收到错误消息时,
ftpServer + fileName的实际值是多少? -
ftp://my.server.no:21/home/username/tmp/01002589006741.TXT这是 ftpserver+filename 的值。使用 UriBuilder 后,它看起来像这样。ftp://username:password@my.server.no:21/home/username/tmp/01002589006741.TXTStille 得到同样的错误..
标签: c# .net ftp stream ftpwebrequest