Java：未报告的异常异常；必须被抓住或宣布被扔掉

Question

我收到此错误：

/student/src/reflection/tester/TestRunnerTests.java:21: error: unreported exception Exception; must be caught or declared to be thrown testRunner.runTests(testClassNames);

所以它表明错误必须在这个类的testRunner.runTests(testClassNames);行：

public class TestRunnerTests {

    @Test
    public void runsTestsFromDecoupledFiles() throws Exception {

        List<String> testClassNames = List.of(
                "reflection.tester.ExampleTests1", "reflection.tester.ExampleTests2");

        TestRunner testRunner = new TestRunner();

        testRunner.runTests(testClassNames);

        String result = testRunner.getResult();

        assertThat(result, containsString("test1() - OK"));
        assertThat(result, containsString("test2() - FAILED"));
        assertThat(result, containsString("test3() - OK"));
        assertThat(result, containsString("test4() - FAILED"));
        assertThat(result, containsString("test5() - OK"));
        assertThat(result, containsString("test6() - FAILED"));

        assertThat(result, not(containsString("helperMethod()")));
    }
}

我的实际代码如下所示：

public class TestRunner{
   List<String> result = new LinkedList<>();
   List<String> annotatedMethods = new LinkedList<>();

   public void runTests(List<String> testClassNames) throws Exception {
       for (String test: testClassNames) {
           Class<?> aClass = Class.forName(test);
           getClassMethods(aClass);
       }
   }
.....
} 

试过这样的东西，但它说A catch statement that catches an exception only to wrap it in a new instance of the same type of exception and throw it should be avoided

try{
   for (String test: testClassNames) {
        Class<?> aClass = Class.forName(test);
        getClassMethods(aClass);
   }  
} catch (Exception e){
   throw new Exception(e);
}

我该如何解决？

Answer 1

如果你抛出异常，你必须在任何地方接住它。所以你需要将方法“runTests”的调用包装成一个try-catch

（一般：您需要在此实例之外捕获抛出的异常）

你写道： testRunner.runTests(testClassNames);

尝试： try{testRunner.runTests(testClassNames);} catch (Exception e) {...}