Oracle PLS-00382：表达式类型错误 06550

Question

我正在尝试使用从我的选择中检索到的 id 值，它是我的循环在我的插入语句中所基于的值。来自 select 的 id 和 TEST_LOG 表中的第二列都是 NUMBER(19,0)。当我用 12345 替换 id 时，它工作正常。有什么想法吗？

BEGIN
  FOR id IN
  (SELECT id FROM t_sample where children is null)
  LOOP
    INSERT INTO TEST_LOG VALUES (my_sequence.nextVal, id, 'sample', current_timestamp);
  END LOOP;
END;

错误：

Error starting at line : 6 in command -
BEGIN
      FOR id IN
      (SELECT id FROM t_sample where children is null)
      LOOP
        INSERT INTO TEST_LOG VALUES (my_sequence.nextVal, id, 'sample', current_timestamp);
      END LOOP;
    END;
Error report -
ORA-06550: line 5, column 69:
PLS-00382: expression is of wrong type
06550. 00000 -  "line %s, column %s:\n%s"
*Cause:    Usually a PL/SQL compilation error.
*Action:

Answer 1

这种混乱是可以理解的。 最好这样写，错误就会发光。

...
FOR record IN
      (SELECT id FROM t_sample where children is null)
      LOOP
        INSERT INTO TEST_LOG VALUES (my_sequence.nextVal, record.id, 'sample', current_timestamp);
      END LOOP;
...