【发布时间】:2013-09-24 02:23:46
【问题描述】:
我的任务是读入一个包含
格式内容的文件 June 17, 1997
July 23, 1997
September 28, 1980
September 31, 1980
Mar. 2, 1980
Apr. 2, 1980
May 3, 1980
Nov 25, 1989
Dec 25, 1989
Jan 3, 1973
我必须将每个日期存储到一个 Date 对象中。如果下一个日期晚于前一个日期,则应从这两个日期创建一个 DateRange 对象。最终输出应该是这样的
Date: June 17, 1997
Date: July 23, 1997
DateRange: Date: June 17, 1997 - Date: July 23, 1997
Date: September 28, 1980
Invalid Date
Date: March 2, 1980
Date: April 2, 1980
DateRange: Date: March 2, 1980 - Date: April 2, 1980
Date: May 3, 1980
DateRange: Date: April 2, 1980 - Date: May 3, 1980
Date: November 25, 1989
DateRange: Date: May 3, 1980 - Date: November 25, 1989
Date: December 25, 1989
DateRange: Date: November 25, 1989 - Date: December 25, 1989
Date: January 3, 1973
首先,很抱歉看到这么长的帖子和这么多要阅读的内容,但我已经解决这个问题一段时间了,我不知道如何继续。我被卡住了,因为我不完全确定如何比较两个日期并将它们放入 DateRange 类。 我的主程序的一个 sn-p 包括:
Scanner in = null;
try {
in = new Scanner(new File("dates.txt"));
} catch (FileNotFoundException exception) {
System.err.println("failed to open dates.txt");
System.exit(1);
}
while (in.hasNextLine()) {
String line = in.nextLine();
Date date = new Date(line);
testDates(date);
if (testDateRange(date) < 0){
System.out.println("There's a range");
}
}
}
public static int testDateRange(Date dates){
return dates.compareTo(dates);
}
public static void testDates(Date dates){
System.out.printf("%s\n", dates.getDate());
//System.out.printf("Date: %s\n", dates.getDate());
}
}
我的 Date 类包括:
public class Date implements Comparable<Date> {
private String dates;
private int year;
private int day;
private int month;
public Date(String line) {
dates = line; // initialize date
} // end one-argument Grades constructor
public String getDate() {
dates = dates.replace(".", "");
dates = dates.replace(",", "");
StringTokenizer st = new StringTokenizer(dates);
String initMonth = st.nextToken();
String initDay = st.nextToken();
String initYear = st.nextToken();
Integer day = Integer.parseInt(initDay);
Integer year = Integer.parseInt(initYear);
String month = initMonth.substring(0,3);
int numMonth = 0;
int maxDays = 0;
String Month = null;
switch (month){
case "Jan":
numMonth = 1;
maxDays = 31;
Month = "January";
break;
case "Feb":
numMonth = 2;
maxDays = 29;
Month = "February";
break;
case "Mar":
numMonth = 3;
maxDays = 31;
Month = "March";
break;
case "Apr":
numMonth = 4;
maxDays = 30;
Month = "April";
break;
case "May":
numMonth = 5;
maxDays = 31;
Month = "May";
break;
case "Jun":
numMonth = 6;
maxDays = 30;
Month = "June";
break;
case "Jul":
numMonth = 7;
maxDays = 31;
Month = "July";
break;
case "Aug":
numMonth = 8;
maxDays = 31;
Month = "August";
break;
case "Sep":
numMonth = 9;
maxDays = 30;
Month = "September";
break;
case "Oct":
numMonth = 10;
maxDays = 31;
Month = "October";
break;
case "Nov":
numMonth = 11;
maxDays = 30;
Month = "November";
break;
case "Dec":
numMonth = 12;
maxDays = 31;
Month = "Decemeber";
break;
default:
break;
}
if(maxDays < day){
dates = ("Invalid Date");
}else{
dates = ("Date: " + Month + " " + day + ", " + year);
}
return dates;
}
public int compareTo (Date other) {
int result = year - other.year;
if (result == 0)
{
result = month - other.month;
if (result == 0)
{
result = day - other.day;
}
}
if (result > 0) return 1;
else if (result < 0) return -1;
else return 0;
}
}
我关心的是 Date 类,我需要比较两个日期。在我的 compareTo() 方法中,我知道它总是会返回 0,因为我没有正确实现它。我只是对如何实现这个 compareTo() 方法感到困惑,实际上将第一个日期与第二个日期进行比较,将第二个日期与第三个日期进行比较,依此类推。而且我目前没有 DateRange 类,因为我无法测试两个日期以查看它们是否有范围。
【问题讨论】:
-
如何将日期转换为毫秒然后减去它们。例如:date1.getTime()-date2.getTime()
-
首先使用
SimpleDateFormat(可能的)格式为MMMM d, yyyy,将Strings 解析为Dates。然后使用Date#before或Date#after来确定日期之间的关系... -
我主要关心的是如何同时访问 date1 和 date2?我可以比较它们,我只是不知道如何同时访问它们
-
我应该将日期存储在数组中吗?