用于获取两个日期之间的第 n 个工作日日期的 SQL 查询

Question

我的场景如下：

@StartDate = 13th of current month
@EndDate = 12th of next month.

我想获取所有日期，其中星期一、星期二、星期三、星期四、星期五、星期六和星期日的日期名称介于开始日期和结束日期之间。

Answer 1

试试这个：

declare @startDate datetime = '2016-01-13'
declare @endDate datetime = '2016-02-12'

;with dateRange as
(
  select [Date] = dateadd(dd, 1, @startDate)
  where dateadd(dd, 1, @startDate) < @endDate
  union all
  select dateadd(dd, 1, [Date])
  from dateRange
  where dateadd(dd, 1, [Date]) < @endDate
)

select [Date], datename(dw,[Date])
from dateRange

Answer 2

要根据您的评论计算每天的数量（这确实应该是问题的一部分），请更改詹姆斯对此回答的最后一部分：

select datename(dw,[Date]) as day_name, count([Date]) as number_days
from dateRange group by datename(dw,[Date]), datepart(DW,[Date])
order by datepart(DW,[Date]);

Answer 3

你可以试试这样的：

DECLARE @StartDate DATETIME
DECLARE @StartDateFixed DATETIME
DECLARE @EndDate DATETIME
DECLARE @NumberOfDays int


SET @StartDate = '2016/01/01'
SET @EndDate = '2016/01/02'
SET @NumberOfDays = DATEDIFF(DAY,@StartDate,@EndDate) + 1 

SET @StartDateFixed = DATEADD(DD,-1,@StartDate)

SELECT  WeekDay , COUNT(WeekDay) 
FROM  (
        SELECT TOP (@NumberOfDays) WeekDay = DATENAME(DW , DATEADD(DAY,ROW_NUMBER() OVER(ORDER BY spt.name), @StartDateFixed))    
        FROM   [master].[dbo].[spt_values] spt 
      ) A
GROUP BY WeekDay

输出将是

WeekDay                        
------------------------------ -----------
Friday                         1
Saturday                       1

(2 row(s) affected)

Answer 4

如果您需要从指定的日期编号（例如 13 和 12）获取当前日期和下一个日期

当前月份

DECLARE @cur_mont INT =  (SELECT MONTH(GETDATE()))

当年

DECLARE @cur_year INT = (SELECT YEAR(GETDATE()))

下个月

DECLARE @nxt_mont INT = (SELECT MONTH(DATEADD(month, 1, GETDATE())))

下个月年（如果十二月年变化）

DECLARE @nxt_year INT = (SELECT YEAR(DATEADD(month, 1, GETDATE())))

创建开始日期

DECLARE @startDate DATETIME = (SELECT CAST(CAST(@cur_year AS varchar) + '-' + CAST(@cur_mont AS varchar) + '-' + CAST(13 AS varchar) AS DATETIME))

创建结束日期

DECLARE @endDate DATETIME = (SELECT CAST(CAST(@nxt_year AS varchar) + '-' + CAST(@nxt_mont AS varchar) + '-' + CAST(12 AS varchar) AS DATETIME))

开始日期和结束日期之间的日期

SELECT  TOP (DATEDIFF(DAY, @startDate, @endDate) + 1)
    DATEADD(DAY, ROW_NUMBER() OVER(ORDER BY a.object_id) - 1, @startDate) AS Date,
    DATENAME(DW, DATEADD(DAY, ROW_NUMBER() OVER(ORDER BY a.object_id) - 1, @startDate)) AS Day
    FROM sys.all_objects a CROSS JOIN sys.all_objects b;

Answer 5

DECLARE @dayStart int = 13, --The day of current month
        @dayEnd int = 12,   --The day of another month
        @howManyMonth int = 1, --How many month to take
        @dateStart date,
        @dateEnd date
--Here we determine range of the dates
SELECT @dateStart = CONVERT (date,
        CAST(DATEPART(Year,GETDATE()) as nvarchar(5))+ '-' + 
        CASE WHEN LEN(CAST(DATEPART(Month,GETDATE()) as nvarchar(5))) = 1 
             THEN '0'+CAST(DATEPART(Month,GETDATE()) as nvarchar(5)) 
             ELSE CAST(DATEPART(Month,GETDATE()) as nvarchar(5)) END + '-' +
        CAST (@dayStart as nvarchar(5))),
        @dateEnd = CONVERT (date,
        CAST(DATEPART(Year,DATEADD(Month,@howManyMonth,GETDATE())) as nvarchar(5))+ '-' + 
        CASE WHEN LEN(CAST(DATEPART(Month,DATEADD(Month,@howManyMonth,GETDATE())) as nvarchar(5))) = 1 
             THEN '0'+CAST(DATEPART(Month,DATEADD(Month,@howManyMonth,GETDATE())) as nvarchar(5)) 
             ELSE CAST(DATEPART(Month,DATEADD(Month,@howManyMonth,GETDATE())) as nvarchar(5)) END + '-' +
        CAST (@dayEnd as nvarchar(5)))

;WITH cte AS (
SELECT @dateStart as date_
UNION ALL
SELECT DATEADD(day,1,date_) 
FROM cte
WHERE DATEADD(day,1,date_) <= @dateEnd
)
--Get results
SELECT  DATENAME(WEEKDAY,date_) as [DayOfWeek], 
        COUNT(*) as [DaysCount]
FROM cte
GROUP BY    DATEPART(WEEKDAY,date_),
            DATENAME(WEEKDAY,date_)
ORDER BY DATEPART(WEEKDAY,date_)
OPTION (MAXRECURSION 0)

输出：

DayOfWeek   DaysCount
----------- -----------
Sunday      4
Monday      4
Tuesday     4
Wednesday   5
Thursday    5
Friday      4
Saturday    4

(7 row(s) affected